Answer:
=46.27in
Step-by-step explanation:
2

Suggesting that you want this in standard form, in terms of quadratic equations, you would technically follow a process similar if not almost exactly like the 2 - step equation method with the exception of separating the (x)s and the equations to find x and then plug it in and what-not.
With that being said you would subtract 5 in (x+5) from said 5 in the second equation and -10 in the first equation in order to get 2x^2+7x-15, you would continue to do the same for the x by subtracting it from both ends making the 7x a 6x because there is a 1 at the beginning of each x if there is no number that is shown already. Which finally gives you the equation (y= 2x^2+6x-15)
Answer:
![y=[1]cos([\frac{2\pi }{3}]x)](https://tex.z-dn.net/?f=y%3D%5B1%5Dcos%28%5B%5Cfrac%7B2%5Cpi%20%7D%7B3%7D%5Dx%29)
Step-by-step explanation:
Looking at the graph, we can see the domain to be from (0 , 2π).
Now we have to find one period that corresponds to cos(x).
The half-period of cos(x) for this graph appears to be pi/3 and adding another pi/3 gets us 2pi/3 to be our cosine period.
b = 2pi/3
a is the same range as cos(x). Range: (0,0)
y = [a] * cos ([b]*x)
y = [1] * cos([2pi/3]x)
Answer: If the dimension of V is n, then V has n elements.
Now, dim(U) + dim(W) = n, this means that the addition of the dimensions of U and W also has n elements.
and because U and W are subspaces of V, you know that every element on U and W is also an element of V.
If U ∩ W = ∅, means that there are no elements in common between U and W.
Because there are no elements in common, then Dim(U) + Dim(W) = dim(U ∪ W) = n
So U ∪ W has the same number of elements as V, and every element of W and U is also an element of V
this means that U ∪ W = V.