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3 years ago

Which cylinder has a volume of 457 cm?

Mathematics

1 answer:

KIM [24]3 years ago

5 0

Answer:

third one

(radius 3 and height 5)

Step-by-step explanation:

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Solve the equation for x. 6x = –54

Romashka [77]

Divide each term by 6 and simplify.

x = −9

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2 years ago

Read 2 more answers

a city’s average temperature over five months is shown in the graph. which statement is not true of the data

mrs_skeptik [129]

Answer: March to April shows the least increase of average temperature.

5 0

2 years ago

Simplify (65)2 O A. 670 O B. 67 C. 65 D. 63

Ket [755]

130 If you multiply that’s what it would give you so I’m not sure what those answers are

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3 years ago

Find the measure of the missing angles.

sukhopar [10]

Answer:

B= 133° C= 47°

Step-by-step explanation:

As shows on the right it's 133°

A= 133°

c+a =180° -a

= 180° -133°

=47°

a and c complement each other and

b= a = 133°

a and b are vertical angles

If you like my answer please click the brainiest thank you!

8 0

2 years ago

Find maclaurin series

Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

$\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}$

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

$\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}$

The first 3 terms of the series are

$\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}$

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

$\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}$

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

$\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}$

7 0

2 years ago