3 years ago

3,153,007 nearest 100,000

Mathematics

1 answer:

Oksi-84 [34.3K]3 years ago

4 0

The nearest 100,000 is 3,200,000

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4 years ago

Evaluate the integral using integration by parts with the indicated choices of u and dv. (Use C for the constant of integration.

trasher [3.6K]

Answer:

$\frac{xe^{7x}}{7} + \frac{e^{7x}}{49}$

Step-by-step explanation:

Given the integral equation

$\int\limits{xe^{7x}} \, dx \\$

According to integration by part;

$\int\limits {u} \, dv = uv + \int\limits {v} \, du$

u = x, dv = e^7x

du/dx = 1

du = dx

$v = \int\limits {e^{7x}} \, dx \\v = e^7x/7$

Substitute the given values into the formula;

$\int\limits {xe^{7x}} \, dx = x(e^{7x}/7) + \int\limits ({e^{7x}/7}) \, dx\\\int\limits {xe^{7x}} \, dx = \frac{xe^{7x}}{7} + \frac{e^{7x}}{7*7} \\\int\limits {xe^{7x}} \, dx = \frac{xe^{7x}}{7} + \frac{e^{7x}}{49}$

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3 years ago

Find the points of intersection of the following function graphs: y=20x−70 and y=70x+30

LekaFEV [45]

Answer:

(-2,-110)

Step-by-step explanation:

First solve for x

20x−70=70x+30

x= -2

Now substitute x for -2

y=20x−70

y=20(-2)-70

y = -110

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