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Alchen [17]
4 years ago
9

How to solve -5/7-11/7x=-y 2y=7+5x

Mathematics
1 answer:
Oliga [24]4 years ago
6 0
\left\{\begin{array}{ccc}-\frac{5}{7}-\frac{11}{7}x=-y&/\cdot(-1)\\2y=7+5x\end{array}\right\\\left\{\begin{array}{ccc}\frac{5}{7}+\frac{11}{7}x=y\\2y=7+5x\end{array}\right\\\\substitute\\\\2\cdot\left(\frac{5}{7}+\frac{11}{7}x\right)=7+5x\\\\\frac{10}{7}+\frac{22}{7}x=7+5x\ \ \ /\cdot7\\\\10+22x=49+35x\\\\22x-35x=49-10\\\\-13x=39\ \ \ /:(-13)\\\\x=-3

\left\{\begin{array}{ccc}x=-3\\y=\frac{5}{7}+\frac{11}{7}x\end{array}\right\\\left\{\begin{array}{ccc}x=-3\\y=\frac{5}{7}+\frac{11}{7}\cdot(-3)\end{array}\right\\\left\{\begin{array}{ccc}x=-3\\y=\frac{5}{7}-\frac{33}{7}\end{array}\right\\\left\{\begin{array}{ccc}x=-3\\y=-\frac{28}{7}\end{array}\right\\\left\{\begin{array}{ccc}x=-3\\y=-4\end{array}\right
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Step-by-step explanation:

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