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ivann1987 [24]
4 years ago
14

An experiment involves 16 participants. From these, a group of 4 participants is to be tested under a special condition. How man

y groups of 4 participants can be chosen, assuming that the order in which the participants are chosen is irrelevant? (If necessary consult a list of formulas.)
Mathematics
1 answer:
zheka24 [161]4 years ago
6 0

Answer:

43,680 ways.

Step-by-step explanation:

We have been given that an experiment involves 16 participants. From these, a group of 4 participants is to be tested under a special condition. We are asked to find the number of groups of 4 participants that can be chosen, assuming that the order in which the participants are chosen is irrelevant.

We will use permutations formula to solve our given problem.

^nP_r=\frac{n!}{(n-r)!}

For our given problem n=16 and r=4.

^{16}P_4=\frac{16!}{(16-4)!}

^{16}P_4=\frac{16!}{12!}=\frac{16*15*14*13*12!}{12!}=16*15*14*13=43,680

Therefore, 4 participants can be chosen in 43,680 different ways.  

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