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tatyana61 [14]
3 years ago
10

One of the zeros of the quadratic equation x^2=9 is 3. Find the other zero. x =

Mathematics
1 answer:
Nataly [62]3 years ago
5 0
X^2 = 9 
x = ± √9
x = ± 3

x1 = 3
x2 = - 3
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evablogger [386]

Answer: 20 students participate in school sports.

Step-by-step explanation:

Since, Mrs. Perez has 28 students.

And, According to the question, 5 /7 of those students participate in school sports.

Therefore, the students participate in school sports = 5/7 of the total number of the students

= 5/7 \times 28

= 20

Thus 20 students participate in school sports.


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Find the diameter of a circle with circumference of 15.70
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Find the diameter of a circle with circumference of 15.70

Solution: We are given:

The circumference of a circle =15.70

We are required to find the diameter of the circle based on given circumference.

We know that:

Diameter = \frac{circumference}{\pi}  

                      =\frac{15.70}{3.1416}      \because \pi \approx 3.1416

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7 0
3 years ago
A system consists of two components C1 and C2, each of which must be operative in order for the overall system to function. Let
hram777 [196]

Answer:

The reliability of the first system to work is 0.72 whereas the reliability of the second system to work is 0.98.As the reliability of the second system is more than the first one so the second system is more reliable.

Step-by-step explanation:

For first system as given in the attached diagram gives,

P(W_1W_2)=P(W_1) \times P(W_2)

As the systems are independent.

The given data indicates that

  • P(W_1) is given as 0.9
  • P(W_2) is given as 0.8

Now the probability of the system is given as

P(W_1W_2)=P(W_1) \times P(W_2)\\P(W_1W_2)=0.9 \times 0.8\\P(W_1W_2)=0.72

So the reliability of the first system to work is 0.72.

For the second system is given as

P(W_1W_2)=1-P(W_1'W_2')

Where

  • P(W_1'W_2') is the probability where both of the systems does not work. this is calculated as

P(W_1'W_2')=P(W_1') \times P(W_2')\\P(W_1'W_2')=(1-P(W_1)) \times (1-P(W_2))\\P(W_1'W_2')=(1-0.9) \times (1-0.8)\\P(W_1'W_2')=(0.1) \times (0.2)\\P(W_1'W_2')=0.02

So now the probability of the second system is given as

P(W_1W_2)=1-P(W_1'W_2')\\P(W_1W_2)=1-0.02\\P(W_1W_2)=0.98

So the reliability of the second system to work is 0.98.

As the reliability of the second system is more than the first one so the second system is more reliable.

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2. Valcor wants to bike at least 120 miles this week. He already went on a bike ride on Monday for 20.
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Answer:

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Step-by-step explanation:

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