One of the zeros of the quadratic equation x^2=9 is 3. Find the other zero. x =

Given f(x)=3x^2+5 and g(x)=x−2 . What is (fg)(x) ? 3x^2−x+7 3x^3−6x2+5x−10 −3x^2+x−7 3x^3−10

wolverine [178]

For this case we have that by definition:

$(fg) (x) = f (x) * g (x)$

So:

$(fg) (x) = (3x ^ 2 + 5) (x-2)$

We apply distributive property that states that:

$(a + b) (c + d) = ac + ad + bc + bd$

In addition, we take into account that:

$+ * - = -$

$(fg) (x) = 3x ^ 3-6x ^ 2 + 5x-10$

Answer:

$3x ^ 3-6x ^ 2 + 5x-10$

Option B

6 0

2 years ago

Read 2 more answers

Which of the following is a decomposition reaction?

atroni [7]

Answer:

Reactant plus reactant yields product.

Step-by-step explanation:

A decomposition reaction starts from a single substance and produces more than one substance. One substance as a reactant and more than one substance as the products is the key characteristic of a decomposition reaction.

Hope this helps.

4 0

2 years ago

Rewrite the form In exponential form: Log100 = x

andrey2020 [161]

Answer:

$10^x=100$

Step-by-step explanation:

You know how subtraction is the opposite of addition and division is the opposite of multiplication? A logarithm is the opposite of an exponent. You know how you can rewrite the equation 3 + 2 = 5 as 5 - 3 = 2, or the equation 3 × 2 = 6 as 6 ÷ 3 = 2? This is really useful when one of those numbers on the left is unknown. 3 + _ = 8 can be rewritten as 8 - 3 = _, 4 × _ = 12 can be rewritten as 12 ÷ 4 = _. We get all our knowns on one side and our unknown by itself on the other, and the rest is computation.

We know that $3^2=9$ ; as a logarithm, the exponent gets moved to its own side of the equation, and we write the equation like this: $\log_3{9}=2$ , which you read as "the logarithm base 3 of 9 is 2." You could also read it as "the power you need to raise 3 to to get 9 is 2."

One historical quirk: because we use the decimal system, it's assumed that an expression like $\log1000$ uses base 10, and you'd interpret it as "What power do I raise 10 to to get 1000?"

The expression $\log100=x$ means "the power you need to raise 10 to to get 100 is x," or, rearranging: "10 to the x is equal to 100," which in symbols is $10^x=100$ .