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Gre4nikov [31]
3 years ago
14

Triangle XYZ has vertices X(-3,-2),Y(-1,0), and Z(1,-6). Find the vertices of triangle XYZ after a translation of 6 units to the

right. Then graph the triangle and its image
Mathematics
1 answer:
GREYUIT [131]3 years ago
4 0

Answer:

C. X’(–1, 1), Y’(–3, –4), Z’(–5, 1)

Step-by-step explanation:

To be honest all you do is plot and translate and when you plot you get your image and pre-image and whatever the points are for your pre-image on the graph that is your answer...hope this helps :)

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gavmur [86]

Answer: the third choice.

Step-by-step explanation:

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You buy $16 worth of food at a restaurant. The sales tax is 5.75% and you wish to tip 10%. What is the bill after tax, how much
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Sales tax on food = total cost of food x sales tax = $16 x 5.75% = $0.92
Bill after tax = total cost of food + sales tax on food = $16 + $0.92 = $16.92
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Total bill = bill after tax + tip owed = $16.92 + $1.60 = $18.52
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3 years ago
Please can you help me???
4vir4ik [10]

Answer:

17\sqrt{2}

Step-by-step explanation:

7 0
2 years ago
Solve algebraically for all values of x:<br> 8x^4-70x^3-18x^2
Lunna [17]

Answer:

x= 0

x= 9

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Step-by-step explanation:

(look at the pic I posted)

8 0
2 years ago
A plane can fly 540 miles with the wind in one hour less than it can fly 480 miles against the wind. The average wind speed is 3
Bess [88]

Answer:

The speed of the plane in still air = 150 mph

Step-by-step explanation:

This is a relative velocity question

Let the velocity of the plane in still air be v

And let the time the plane can fly 480 miles against the wind be t

(Velocity of the plane relative to the wind) = (velocity of plane) - (velocity of wind)

Flying against the wind

(Velocity of plane relative to the wind) = (480/t)

(Velocity of the plane) = v

(Velocity of the wind) = 30 mph

(480/t) = v - 30

t = 480/(v-30) (eqn 1)

Flying with the wind

(Velocity of plane relative to the wind) = 540/(t-1)

(Velocity of the plane) = v

(Velocity of the wind) = -30 mph

540/(t - 1) = v + 30

t - 1 = 540/(v+30) (eqn 2)

Since t is equal in both cases, substitute the value of t in eqn 1 into eqn 2.

[480/(v-30)] - 1 = [540/(v+30)]

Multiply through by (v+30)(v-30)

480(v+30) - [(v+30)(v-30)] = 540(v-30)

480v + 14400 - (v² - 900) = 540v - 16200

480v + 14400 - v² + 900 = 540v - 16200

v² + 540v - 480v - 16200 - 14400 - 900 = 0

v² + 60v - 31500 = 0

Solving the quadratic equation,

v = 150 mph or v = -210 mph

We'll pick the positive answer because of the directions we have established.

Therefore, the speed of the plane in still air = 150 mph

Hope this Helps!!!

3 0
2 years ago
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