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kakasveta [241]
3 years ago
9

A two-story building measures 21 feet from the ground.Ascale model shows the building to be 3 inches tall. How many inches would

an 84 foot building be in the model?
Mathematics
1 answer:
jasenka [17]3 years ago
4 0

Answer: 12\ inches

Step-by-step explanation:

Let be "x" the height inches (in the model) of a 84 foot building.

According to the information provided in the exercise, we know that the height of a two-story building is 21 feet and in the scale model its height is 3 inches.

Knowing this, we can set up the following proportion:

\frac{3}{21}=\frac{x}{84}

The final step is to solve for "x" in order to calculate its value. We get that this is:

\frac{3}{21}=\frac{x}{84}\\\\(84)(\frac{3}{21})=x\\\\x=12

Therefore,  an 84 foot building will be 12 inches tall in the model.

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Which best explains how the division equation relates to the diagram? (11 7/8) ÷ (2 3/8) =5
xxMikexx [17]

Answer:

When you split the fraction 2\frac{3}{8} into 5 parts it will equal to 11\frac{7}{8}.

Step-by-step explanation: I hope this helps. UwU


4 0
3 years ago
A lawn with an area of 300 square feet needs 1/2 pound of grass seed. How many pounds of grass seed are needed for a lawn that i
lana66690 [7]
2 pounds.

60(20) = 1200 = area
If 300 square feet requires 1/2 pound, you can divide 1200 square feet by 300 square feet.

1200/300=4
4 times 1/2
4(1/2)=2

For every 300 square feet, you need half a pound. If you were to have 600 square feet, you would need a pound of grass seed. Therefore, for 1200 square feet, you need 2 pounds of grass seed.
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3 years ago
F ind the volume under the paraboloid z=9(x2+y2) above the triangle on xy-plane enclosed by the lines x=0, y=2, y=x
olga nikolaevna [1]

Answer:

The answer is 48 units³

Step-by-step explanation:

If we simply draw out the region on the x-y plane enclosed between these lines we realize that,if we evaluate the integral the limits all in all cannot be constants since one side of the triangular region is slanted whose equation is given by y=x. So the one of the limit of one of the integrals in the double integral we need to evaluate must be a variable. We choose x part of the integral to have a variable limit, we could well have chosen y's limits as non constant, but it wouldn't make any difference. So the double integral we need to evaluate is given by,

V=\int\limits^2_0 {} \, \int\limits^{x=y}_0 {z} \, dx dy\\V=\int\limits^2_0 {} \, \int\limits^{x=y}_0 {9(x^{2}+y^{2})} \, dx dy

Please note that the order of integration is very important here.We cannot evaluate an integral with variable limit last, we have to evaluate it first.after performing the elementary x integral we get,

V=9\int\limits^2_0 {4y^{3}/3} \, dy

After performing the elementary y integral we obtain the desired volume as below,

V= 48 units^{3}

4 0
3 years ago
Bustin bought a DVD player that was marked down from $150 to $100. find the percent of decrease​
Leno4ka [110]
33% of decrease.

150-100=50

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1/3= 33%
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3 years ago
Find the slope of the line that passes through (80, 300) and (70, 500).
olga2289 [7]

Answer:

m = -20

Step-by-step explanation:

3 0
3 years ago
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