Answer:
Amplitude 3; midline y=2
Step-by-step explanation:
The midline is the mean of both ends of the function in the graph.
The amplitude is the vertical distance between the midline and one of the end points.
(sorry for the basic math, i just want to make sure you know where im getting the values from)
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>☝</em><em>☝</em><em>✌</em><em>✌</em><em>✌</em><em>✌</em>
g(x) = (1/4)x^2 . correct option C) .
<u>Step-by-step explanation:</u>
Here we have , and we need to find g(x) from the graph . Let's find out:
We have , . From the graph we can see that g(x) is passing through point (2,1 ) . Let's substitute this point in all of the four options !
A . g(x) = (1/4x)^2
Putting (2,1) in equation g(x) = (x/4)^2 , we get :
⇒
⇒
Hence , wrong equation !
B . g(x) = 4x^2
Putting (2,1) in equation g(x) = 4x^2 , we get :
⇒
⇒
Hence , wrong equation !
C . g(x) = (1/4)x^2
Putting (2,1) in equation g(x) = (1/4)x^2 , we get :
⇒
⇒
Hence , right equation !
D . g(x) = (1/2)x^2
Putting (2,1) in equation g(x) = (1/2)x^2 , we get :
⇒
⇒
Hence , wrong equation !
Therefore , g(x) = (1/4)x^2 . correct option C) .
