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Hunter-Best [27]
3 years ago
11

In order to join a dancing club there is a $30 startup fee and a $4 monthly fee. If you joined the club and spent $82, how many

months did attend the club?
help needed urgently?
Mathematics
1 answer:
kap26 [50]3 years ago
3 0

Answer:

<u>13</u> months attended the club.

Step-by-step explanation:

Given:

In order to join a dancing club there is a $30 startup fee and a $4 monthly fee. If you joined the club and spent $82.

Now, to find the months attend the club.

Startup fee = $30.

Monthly fee = $4.

Total money spent = $82.

So, we deduct the startup fee from the total money spent:

82-30

=\$52.

The remaining amount is $52.

Now, we divide the monthly fee by the remaining amount to get the months attended:

52\div 4

=13.

Therefore, 13 months attended the club.

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Use the definition of continuity and the properties of limit to show that the function f(x)=x sqrtx/ (x-6)^2 is continuous at x=
jasenka [17]

Answer:

The function \\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}} is continuous at x = 36.

Step-by-step explanation:

We need to follow the following steps:

The function is:

\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}

The function is continuous at point x=36 if:

  1. The function \\ f(x) exists at x=36.
  2. The limit on both sides of 36 exists.
  3. The value of the function at x=36 is the same as the value of the limit of the function at x = 36.

Therefore:

The value of the function at x = 36 is:

\\ f(36) = \frac{36*\sqrt{36}}{(36-6)^{2}}

\\ f(36) = \frac{36*6}{900} = \frac{6}{25}

The limit of the \\ f(x) is the same at both sides of x=36, that is, the evaluation of the limit for values coming below x = 36, or 33, 34, 35.5, 35.9, 35.99999 is the same that the limit for values coming above x = 36, or 38, 37, 36.5, 36.1, 36.01, 36.001, 36.0001, etc.

For this case:

\\ lim_{x \to 36} f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}

\\ \lim_{x \to 36} f(x) = \frac{6}{25}

Since

\\ f(36) = \frac{6}{25}

And

\\ \lim_{x \to 36} f(x) = \frac{6}{25}

Then, the function \\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}} is continuous at x = 36.

8 0
3 years ago
I need help with this!
sertanlavr [38]

Answer:

67 degrees

Step-by-step explanation:

first find angle abc by subtracting 68 from 101 == 33

then add it to half of 68 (34) to get angle abe

we know it is half because if there is a bisector, both angles cbe and ebd are equal

8 0
3 years ago
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koban [17]
Answer letter b I think
7 0
3 years ago
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A rectangle length was 4 feet longer than triple the length of it width
wlad13 [49]
Length is 48 ft

The perimeter of a rectangle is equal to the sum of all side’s.
2(lengths)+2(widths)= perimeter
Length=3x+4
Now given the perimeter of 140
3(3x+4)+3(x)=140
9x+12+3x=140
12x+12=140
12x=128
X= 10.7
10.7 is the width

Length=3x+4
Length =3(10.6)+4
Length=31.8+4
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This can only be answered if you were given a perimeter.
4 0
4 years ago
Determine the measure of angle A, to the nearest degree.
Effectus [21]

Answer:

(a) 17°

(b) 78°

Step-by-step explanation:

(a) sin A= 0.2896

to calculate for "A" check for sin inverse of 0.2896

A= sin^-1(0.2896) = 16.83

to the nearest degree A= 17°

(b) tan A = 4.7046

A= tan^-1(4.7046)

A = 77.99

to the nearest degree A = 78°

4 0
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