Answer:
The three consecutive integers are 5,6,7
Step-by-step explanation:
Let the three consecutive integers be represented as x,x+1,x+2
As per the requirement, largest integer is 3 less than twice the smallest.
=> x+ 2 = 2x -3
=> 2x -x = 2+3
=> x= 5
So the three integers are 5,6,7
Verification:
Largest integer = 7
Smallest integer = 5
2 * smallest integer - 3 = 2* 5 - 3 = 7
Largest integer is also 7.
So the required condition in the question is satisfied by these three integers.
Answer:
Step-by-step explanation:
Area of square = area of triangle
![side*side = \dfrac{1}{2}b*h\\\\\\x*x=\dfrac{1}{2}*(x+1)(x+2)\\x^{2}=\dfrac{1}{2}[x*x +x*2+1*x+1*2]\\\\\\x^{2}=\dfrac{1}{2}[x^{2}+2x+x+2]\\\\\\x^{2}=\dfrac{1}{2}[x^{2}+3x+2]\\\\\\Multiply \ both \ sides \ by \ 2\\\\2x^{2}=x^{2}+3x+2\\\\2x^{2}-x^{2}-3x-2 = 0](https://tex.z-dn.net/?f=side%2Aside%20%3D%20%5Cdfrac%7B1%7D%7B2%7Db%2Ah%5C%5C%5C%5C%5C%5Cx%2Ax%3D%5Cdfrac%7B1%7D%7B2%7D%2A%28x%2B1%29%28x%2B2%29%5C%5Cx%5E%7B2%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5Bx%2Ax%20%2Bx%2A2%2B1%2Ax%2B1%2A2%5D%5C%5C%5C%5C%5C%5Cx%5E%7B2%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5Bx%5E%7B2%7D%2B2x%2Bx%2B2%5D%5C%5C%5C%5C%5C%5Cx%5E%7B2%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5Bx%5E%7B2%7D%2B3x%2B2%5D%5C%5C%5C%5C%5C%5CMultiply%20%5C%20both%20%5C%20sides%20%5C%20by%20%5C%202%5C%5C%5C%5C2x%5E%7B2%7D%3Dx%5E%7B2%7D%2B3x%2B2%5C%5C%5C%5C2x%5E%7B2%7D-x%5E%7B2%7D-3x-2%20%3D%200)
x² - 3x - 2 = 0
Answer:
1/ 5 and 2/3
cross multiple
example
1 2 = 10
/ x / = /
5 3 3
= 10/3
so it's 3 1/3 + 10 Mm
so may guess is
13.3333 infinite or 13.34 M
Dont know if its right but good luck
Answer:
is correct, he determines it correctly, he solved it correctly, 238.5
Step-by-step explanation:
