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ycow [4]
3 years ago
7

Please help with math problem

Mathematics
1 answer:
maksim [4K]3 years ago
7 0

Answer:

a_0 = -6

a_1=8

x^2 +y^2 -6x + 8y = 0

Step-by-step explanation:

The equation of the circle has the following form

x^2 + y^2 + a_0x + a_1y=0

The equation of the circle has the following form

We know that the circle goes through the following points

(0, 0)

(6, 0)

(0, -8).

Then we substitute the values of x and y in the equation

<u>For (0, 0)</u>

0^2 + 0^2 + a_0(0) + a_1(0)=0

0=0

<u>For  (6, 0)</u>

6^2 + 0^2 + a_0(6) + a_1(0)=0

36 + 6a_0=0

a_0 = -\frac{36}{6}\\\\a_0 = -6

<u>For (0, -8)</u>

0^2 + (-8)^2 + a_0(0) + a_1(-8)=0

(-8)^2 - 8a_1=0

(-8)^2 = 8a_1

a_1=8

Finally the equation is:

x^2 +y^2 -6x + 8y = 0

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