(2^6)=1
take log on both sides,
xlog(2^6)=log(1)=0
=>
x=0, since log(2^6)>0
5^0=1
there is no value of x appearing in the equation, so x can be any valid number.
2+4z-18
change it so it's an equation
2+4z-18=0
then get 4z alone on one side by subtracting 4z from both sides
2-18=-4z
-16= -4z
divide both sides by -4
a negative divided by a negative becomes positive
4 =z
plug it in
2+4(4)-18
4x4 is 16
2+16-18=0
0=0
the same can be done for the second one 2+k-8
make it 2+k-8=0
move the k to get it alone so subtract k from both sides
2-8=-1k
-6 = -1K
you can divide by K to make K=6
plug in 2+6-8=0
0=0
Answer:
Step-by-step explanation:
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