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Lubov Fominskaja [6]
3 years ago
5

On two investments totaling $11,500, Peter lost 3% on one and earned 4% on the other. If his net annual receipts were $⁢201, how

much was each investment?
Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
6 0
Total amount of money invested - $11500
X +Y = $11500. ----------(1)
Total yearly interest for thetwo a/c is - $201
-0.03X + 0.04Y = $201
Form (1)
X = 11500 - Y
Substitute for X
-0.03(11500 - Y) + 0.04 Y = $201
-345 + 0.03Y + 0.04Y =201
0.07Y = 546
Y = 7800 at 4 %
Calculate X
X = 11500 - Y
= 11500 - 7800
=3700 at - 3%
Check
-0.03×3700 + 0.04 × 7800 = $201
-111 + 312 = $201
$201 = $201
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Which one i greater 2/8 or 1/2 ?
ryzh [129]
\frac{2}{8}=\frac{1}{4}\\
\frac{1}{2}=\frac{2}{4}\\\\
\frac{2}{4}>\frac{1}{4} \Rightarrow\frac{1}{2}>\frac{2}{8}
5 0
2 years ago
Help me please <br> PLEASEEE
vodka [1.7K]
So you can do 1/2 and then divide it by 1/8.

To divide by a fraction, multiply by its reciprocal.
So;
1/2 / 1/8 = 1/2•8/1

1/2• 8 = 8/2
8/2= 4

So he can fill 4 mugs!!!

Brainliest if i helped!
7 0
3 years ago
Read 2 more answers
2 1/3 + 3/7 divided by 2 1/3 x 1 3/7​
oee [108]

Answer: \frac{29}{35}

Step-by-step explanation:

1. Make sure all your denominators are the same, you can do this by multiplying them all by 3 or 7, 2 and 1/3 would become 2 7/21, 3/7 would become 9/21, 2 and 1/3, would become 2 and 7/21, and so on and so forth, leaving us with

2\frac{7}{21}+\frac{9}{21} / 2\frac{7}{21} * 1\frac{9}{21}

2. Now, I would go and solve each side of the equation because we divide them, we can add 2\frac{7}{21} and \frac{9}{21}  together to get  2\frac{16}{21}, because 7 + 9 = 16

2\frac{16}{21} / 2\frac{7}{21} * 1\frac{9}{21}

3. We can do the same thing to the other side, by multiplying the two of them. I'm going to convert both of them to just fractions, 2\frac{7}{21} becomes \frac{49}{21} and 1\frac{9}{21} becomes \frac{30}{21}

\frac{49}{21} *  \frac{30}{21}

Now we can reduce them, and for our first fraction divide the top and bottom by 7, giving us  \frac{7}{3} and the second one by 3, which gives us  \frac{10}{7}

\frac{7}{3} * \frac{10}{7} now we cross divide, where we replace the 7's with ones because they're right across from each other to get  \frac{1}{3} and  \frac{10}{1}, or just 10.

\frac{1}{3} * 10 =  \frac{10}{3}

4. So now we can do a similar thing with the first half of our equation and convert it into a fraction and not a mixed number.

\frac{58}{21} / \frac{10}{3}

Now we multiply divide them, and the easiest way I learned how to do this was by keep the first fraction in its place, and flipping the denominator and numerator of the second, and multiplying them.

so   \frac{58}{21} * \frac{3}{10} which if we multiply both sides, you get \frac{174}{210}

I'll save you some times and simplify it for you, the greatest common factor is 6 so we divide the top and bottom by 6 to get

\frac{29}{35}

4 0
2 years ago
Find an equation for the line below.<br><br> The points are 5,-2 and -5,-6
horsena [70]

Answer:

y=1/2x-4.5

Step-by-step explanation:

y=mx+b

4 0
2 years ago
Matthew is packing 120 pencils and 108 notebooks
Rasek [7]

9514 1404 393

Answer:

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Step-by-step explanation:

a) The number of boxes will be the greatest common divisor (GCD) of the numbers 120 and 108. That number is 12.

  120 = 12×10

  108 = 12×9 . . . . 12 is the greatest common divisor

Matthew can make 12 boxes with equal numbers of the items.

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b) 120 pencils divided by 12 will be 10 pencils per box.

108 notebooks divided by 12 will be 9 notebooks per box.

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<em>Additional comment</em>

It helps to be familiar with multiplication tables up to about 12×12.

The GCD can always be found using Euclid's algorithm. Look at the remainder when the larger number is divided by the smaller. If it is not zero, then replace the larger number with the remainder and repeat. If the remainder is zero, the divisor is the GCD.

Here, we have ...

  120/108 = 1 r 12.

  108/12 = 9 r 0   ⇒   12 is the GCD

7 0
3 years ago
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