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2 years ago

Easy volume problem.

Mathematics

2 answers:

bagirrra123 [75]2 years ago

5 0

Volume = l×b×h = 48×40×30 = 57600 cm²

svp [43]2 years ago

4 0

Answer:

40*30*48 = 57600

Step-by-step explanation:

V = l*w*h

h = 40

w = 30

l = 48

V = 40*30*48 = 57600

<h2><em><u>57600 is the answer.</u></em></h2>

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Help this confusing no matter how any times I do it

3241004551 [841]

Answer:

The variable 8. Equation is 16 + 12x = 112.

Step-by-step explanation:

We know that she spent $16 dollars on magazines, so we can put it in the equation (16 + x= ?). We also know that the total is $112, so we can also add that (16+ x= 112). We don't know how many books she got, but we do know how much they cost (16 + 12x=112. So that makes the books the variable (X).

To find the variable we need to take out the magazines from the price. 112-16=96. Now we're left with 12x=96. Now all we have to do is divide 96 by 12, which equals 8.

Sorry everything is so long, I tried to make it short as possible

8 0

2 years ago

Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes

azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

The centre of the ellipse is at the origin and the X axis is the major axis

It passes through the points (-3, 1) and (2, -2)

The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

$\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1$

Given that the ellipse passes through the point (-3, 1)

Hence,

$\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1$

Cross multiplying we get,

9b² + a² = 1 ²× a²b²
a²b² = 9b² + a²

Multiply by 4 on both sides,

4a²b² = 36b² + 4a²------(1)

Also by given the ellipse passes through the point (2, -2)

Substituting this,

$\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1$

Cross multiply,

4b² + 4a² = 1 × a²b²
a²b² = 4b² + 4a²-------(2)

Subtracting equations 2 and 1,

3a²b² = 32b²
3a² = 32
a² = 32/3----(3)

Substituting in 2,

32/3 × b² = 4b² + 4 × 32/3
32/3 b² = 4b² + 128/3
32/3 b² = (12b² + 128)/3
32b² = 12b² + 128
20b² = 128
b² = 128/20 = 32/5

Substituting the values in the equation for ellipse,

$\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1$

$\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1$

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>

8 0

2 years ago

if i have and 85 in my class and retook a test that i originally got a 72 what grade would i need for the average to be enough t

viktelen [127]

Assuming there is no specific percentages in the grade book, you would need a grade of 95 to get your whole grade to 90. You find this out by working backwards starting with 90 to find average. You take 90 times 2 which equals 180 and you subtract 85 from that to get 95! Brainliest?

8 0

2 years ago

Skate World offers birthday parties for a fee of $130 plus $3 per person. If you can spend no more than $190 on your party, what

tankabanditka [31]

The max amount of ppl is 20

7 0

2 years ago

Aubrey’s monthly bank statement shows a total of $51 in fees for ATM withdrawals. If Audrey made 17 withdraws, what is Audrey ch

Tpy6a [65]

Answer:

Audrey was charged $3 for each withdrawal.

Step-by-step explanation:

We have to calculate the amount of money charged on one transaction.

In order to find the amount for one ATM withdrawal, the total amount for ATM withdrawals will be divided by number of withdrawals.

Given

$Total\ ATM\ withdrawal\ fees = \$51\\Total\ withdrawals = 17\\Amount\ for\ one\ withdrawal = \frac{Total\ fees}{No.\ of\ withdrawals}\\= \frac{51}{17}\\= \$3$

Hence,

Audrey was charged $3 for each withdrawal.

7 0

2 years ago