Answer:
Kindly check explanation
Step-by-step explanation:
Given that :
The hypothesis :
H0 : σ²= 47.1
H1 : σ² > 47.1
α = 5% = 0.05
Population variance, σ² = 47.1
Sample variance, s² = 83.2
Sample size, n = 15
The test statistic = (n-1)*s²/σ²
Test statistic, T = [(15 - 1) * 83.2] ÷ 47.1
Test statistic = T = [(14 * 83.2)] * 47.1
Test statistic = 1164.8 / 47.1
Test statistic = 24.73
The degree of freedom, df = n - 1 ; 10 = 9
Critical value (0.05, 9) = 16.92 (Chisquare distribution table)
Reject H0 ; If Test statistic > Critical value
Since ; 24.73 > 16.92 ; Reject H0 and conclude that variance is greater.
Answer:
:D
Step-by-step explanation:
I believe the answer would be B. 11 because you can see a pattern. Its just skipping.
Answer:
h = 13cm and b= 54cm.
Step-by-step explanation:
We have that the area
and the base is two centimeters longer than four times the height, that is
![b = 2+4h](https://tex.z-dn.net/?f=b%20%3D%202%2B4h)
where b is the base and h the height. Now, the area is
![A=\frac{b*h}{2}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7Bb%2Ah%7D%7B2%7D)
![351=\frac{(2+4h)h}{2}](https://tex.z-dn.net/?f=351%3D%5Cfrac%7B%282%2B4h%29h%7D%7B2%7D)
![702=2h+4h^2](https://tex.z-dn.net/?f=702%3D2h%2B4h%5E2)
.
Now, we are going to use the general formula to solve quadratic ecuations:
![h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
where a=4, b= 2 and c= -702.
![h=\frac{-2\pm\sqrt{2^2-4(4)(-702)}}{2*4}](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B-2%5Cpm%5Csqrt%7B2%5E2-4%284%29%28-702%29%7D%7D%7B2%2A4%7D)
![h=\frac{-2\pm\sqrt{4+11232}}{8}](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B-2%5Cpm%5Csqrt%7B4%2B11232%7D%7D%7B8%7D)
![h=\frac{-2\pm106}{8}](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B-2%5Cpm106%7D%7B8%7D)
or ![h=\frac{-2-106}{8}](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B-2-106%7D%7B8%7D)
As we are searching for the lenght, we choose the positive result:
![h=\frac{-2+106}{8}=13cm](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B-2%2B106%7D%7B8%7D%3D13cm)
.