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Alexus [3.1K]
2 years ago
11

I NEED HELP WITH 5X+6X

Mathematics
1 answer:
soldier1979 [14.2K]2 years ago
4 0

Answer:

11x

Step-by-step explanation:

Since there like terms you can combine them

5x+6x=11x

if not is there more to this problem so i can fully understand

i hope this helps :)

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Describe and correct the error in writing an equation of the line shown
Rudiy27

Answer:

y  = -\frac{3}{5}x+4

Step-by-step explanation:

Given:

(x_1,y_1) = (0,4)

(x_2,y_2) = (5,1)

The attachment completes the question

From the attachment, the slope of the line was calculated as:

m = \frac{1-4}{0-5}

This step is inaccurate because the slope of a line is calculated using

m = \frac{y_2-y_1}{x_2-x_1}

Which gives

m = \frac{1-4}{5-0}

m = \frac{-3}{5}

m = -\frac{3}{5}

The line equation is then calculated using:

y -y_1 = m(x - x_1)

Substitute values for m, x1 and y1

y - 4 = -\frac{3}{5}(x - 0)

y - 4 = -\frac{3}{5}(x)

Open bracket

y - 4 = -\frac{3}{5}x

Make y the subject

y  = -\frac{3}{5}x+4

6 0
2 years ago
Write the equation of the circle with center (−1, −3) and (−7, −5) a point on the circle.
Pepsi [2]
So, we know the center is at -1, -3, hmmm what's the radius anyway?

well, the radius will be the distance from the center to any point on the circle, it just so happen that we know -7, -5 is on it, thus

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ -1 &,& -3~) 
%  (c,d)
&&(~ -7 &,& -5~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
r=\sqrt{[-7-(-1)]^2+[-5-(-3)]^2}\implies r=\sqrt{(-7+1)^2+(-5+3)^2}
\\\\\\
r=\sqrt{36+4}\implies r=\sqrt{40}\\\\
-------------------------------

\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{-1}{ h},\stackrel{-3}{ k})\qquad \qquad 
radius=\stackrel{\sqrt{40}}{ r}
\\\\\\\
[x-(-1)]^2+[y-(-3)]^2=(\sqrt{40})^2\implies (x+1)^2+(y+3)^2=40
5 0
3 years ago
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