The best way to randomly choose the 100 families would be to allow a random number generator to come up with 100 families within a 50 radius of the amusement park.
Using this method would ensure that it is more randomised & not limited to people who come at a specific time or are in a specific area as well as it not be affected by subconscious bias of people when selecting people to survey.
Stan's, Mark's and Wayne's ages are 35 , 36 and 37 years respectively.
<em><u>Explanation</u></em>
Stan's, Mark's and Wayne's ages are <u>consecutive whole numbers</u> and Stan is the youngest and Wayne is the oldest.
So, lets assume that Stan's, Mark's and Wayne's ages are 
and 
Given that, the sum of their ages is 108. So, the equation will be.....
So, Stan's age is 35 years , Mark's age is (35+1)= 36 years and Wayne's age is (35+2)= 37 years.
Answer:
30 blocks
Step-by-step explanation:
60 minutes = 1 hour
For one hour, she will walk 7.5 blocks.
The rate is 7.5blocks per hour.
Multiply this by 4 hours, and you will get 30 blocks.
(7.5)4 = 30
Two triangles are similar if and only if all corresponding angles are equal (congruence), even if the corresponding sides are equal or not, therefore the answer is true because ΔJKL and ΔRST are similar and the statement above demands that "it must be", namely, this is a sufficient condition.
Answer:
Step-by-step explanation:
Let the integer be 6 for even and 7 for odd (say)
For 6, we divide by 2, now get 3. Now we multiply by 3 and add 1 to get 10. Now since 10 is even divide by 5, now multiply by 3 and add 1 to get 16. Now divide by 2 again by 2 again by 2 again by 2 till we get rid of even numbers.
The result is 1, so multiply by 3 and add 1 we get 4 now divide 2 times by 2 to get 1, thus this result now again repeats after 2 times.
Say if we select off number 3, multiply by 3 and add 1 to get 10 now divide by 5, now repeat the same process as above for 5 until we get 1 and it gets repeated every third time.
Thus whether odd or even after some processes, we get 1 and the process again and again returns to 1.
