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Allisa [31]
3 years ago
11

The length of a flower garden is 9 meters. The width of the garden, w, is unknown. If the area of the garden is greater

Mathematics
1 answer:
muminat3 years ago
5 0

Answer:

The width should be more than 5 m. So it can be  6,7 ...

Step-by-step explanation:

The length of a flower garden is = 9 m

The width of a flower garden is   = w

The area of a flower garden > 45 sq. m

The area of a flower garden  = l * b

l * b > 45

9 * b > 45

the width should be more than 5 m. So it can be  6,7 ...

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For number 3 and 4 what are the Mean, Median, Mode, and Range?<br><br> Please help
guapka [62]

Answer:

3 median= 45

4 median=41

Step-by-step explanation:

mean you add the total and you divide by the number of values

mode the most repeated like no.4 is 41

range the highest-the lowest

3 0
3 years ago
Simplify the expression.
Annette [7]
2 that divide sign 6 
use that signt that is with the 24   Answer is 2 sign 6
7 0
3 years ago
Simplify 7h^2+6h^2+5h^2+6h^2-h^2
iogann1982 [59]

Answer:

23h^2

Step-by-step explanation:

These are all like terms so we add/subtract them from left to right.

7h^2+6h^2+5h^2+6h^2-h^2

=   24h^2 - h^2

= 23h^2   (answer)

6 0
3 years ago
A sector of a circle makes a 127° angle at its centre. If the arc of the sector has length 36 mm, find
Veseljchak [2.6K]

Answer:

Approximately 68.5\; \rm mm.

Step-by-step explanation:

Convert the angle of this sector to radians:

\begin{aligned}\theta &= 127^{\circ} \\ &= 127^{\circ} \times \frac{2\pi}{360^{\circ}} \\ &\approx 2.22\end{aligned}.

The formula s = r\, \theta relates the arc length s of a sector of angle \theta (in radians) to the radius r of this sector.

In this question, it is given that the arc length of this sector is s = 36\; \rm mm. It was found that \theta = 2.22 radians. Rearrange the equation s = r\, \theta to find the radius r of this sector:

\begin{aligned} r&= \frac{s}{\theta} \\ &\approx \frac{36\; \rm mm}{2.22} \\ &\approx 16.2\; \rm mm\end{aligned}.

The perimeter of this sector would be:

\begin{aligned}& 2\, r + s \\ =\; & 2 \times 16.2\; {\rm mm} + 36\; {\rm mm} \\ =\; & 68.5\; \rm mm\end{aligned}.

8 0
3 years ago
Given the polynomial 6x3 + 4x2 − 6x − 4, what is the value of the constant 'k' in the factored form? 6x3 + 4x2 − 6x − 4 = 2(x +
CaHeK987 [17]
First you graph it using a graphing calculator, you look at the table of values to find out one point in which y= 0. The first one that comes up is when x=1.
If you don't have a graphing calculator you can use trial and error by inputing some numbers into x until you get y= 0. 

Once you have an x value which makes y=0, you can start factorizing it. 
you divide 6x3 +4x2 -6x - 4 into (x-1) which is when y =0 
to get 6x2+10x+4 

This can be used to write the polynomial as (x-1)(6x2 +10x+4) 
you then factorize the second bracket, 6x2 +10x+4.
you can take the 2 outside to give you 2(3x2 +5x+2) 
you can factorize this to become 2(3x+2)(x+1) 

Now you just substitute your factorized second bracket into your unfactorized second bracket to give you 2(3x+2)(x+1)(x-1).

From this you can deduce that k= 1 
7 0
3 years ago
Read 2 more answers
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