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MariettaO [177]

3 years ago

10

For your biology class, you have taken a number of measurements for a plant growth experiment. You wish to create a chart that s

hows what the progress looks like over time. Which application is best suited for this effort?
Notepad or Paint

Impress or PowerPoint

Writer or Word

Calc or Excel

Computers and Technology

1 answer:

Mamont248 [21]3 years ago

4 0

Calc or excel
Hope this helps

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Which of the following are advantages of<br> assessments? Check all that apply.

garri49 [273]

Can you add a picture of the options

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3 years ago

Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server

sattari [20]

Answer:

The smallest number of servers required is 3 servers

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Explanation:

Given

$Reliability = 99.98\%$

$Individual Servers = 95\%$

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

$p = 95\%\\$

It should be noted that probabilities always add up to 1;

So,

$p + q = 1$ '

Subtract p from both sides

$p - p + q = 1 - p$

$q = 1 - p$

Substitute $p = 95\%\\$

$q = 1 - 95\%$

Convert % to fraction

$q = 1 - \frac{95}{100}$

Convert fraction to decimal

$q = 1 - 0.95$

$q = 0.05$

------------------------------------------------------------------------------------------------

<em>To get an expression for one server</em>

The probabilities of 1 servers having 99.98% reliability is as follows;

$p = 99.98\%$

Recall that probabilities always add up to 1;

So,

$p + q = 1$

Subtract q from both sides

$p + q - q = 1 - q$

$p = 1 - q$

So,

$p = 1 - q = 99.98\%$

$1 - q = 99.98\%$

Let the number of servers be represented with n

The above expression becomes

$1 - q^n = 99.98\%$

Convert percent to fraction

$1 - q^n = \frac{9998}{10000}$

Convert fraction to decimal

$1 - q^n = 0.9998$

Add $q^n$ to both sides

$1 - q^n + q^n= 0.9998 + q^n$

$1 = 0.9998 + q^n$

Subtract 0.9998 from both sides

$1 - 0.9998 = 0.9998 - 0.9998 + q^n$

$1 - 0.9998 = q^n$

$0.0002 = q^n$

Recall that $q = 0.05$

So, the expression becomes

$0.0002 = 0.05^n$

Take Log of both sides

$Log(0.0002) = Log(0.05^n)$

From laws of logarithm $Loga^b = bLoga$

So,

$Log(0.0002) = Log(0.05^n)$ becomes

$Log(0.0002) = nLog(0.05)$

Divide both sides by $Log0.05$

$\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}$

$\frac{Log(0.0002)}{Log(0.05)} = n$

$n = \frac{Log(0.0002)}{Log(0.05)}$

$n = \frac{-3.69897000434}{-1.30102999566}$

$n = 2.84310893421$

$n = 3 (Approximated)$

<em>Hence, the smallest number of servers required is 3 servers</em>

6 0

3 years ago

In a three-tier architecture, the component that runs the program code and enforces the business processes is the:_______.

madam [21]

Answer:

Application Server

Explanation:

The Application Server is a component in computer engineering that presents the application logic layer in a three-tier architecture.

This functionality allows client components to connect with data resources and legacy applications.

In this process of interaction, the Application Server runs the program code from Tier 1 - Presentation, through Tier 2 - Business Logic to Tier 3 - Resources, by forcing through the business processes.

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3 years ago

lenny joggy along a trail for 1.35 hours he ran at a pace of 3.2 miles per hour. how far did lenny jog?

Dmitriy789 [7]

Answer:

Lenny jogged along a trail for 1.35 hours. He ran at a pace of 3.2 miles per hour. How far did Lenny jog? Answer Lenny jogged 4.32 miles.

Explanation:

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2 years ago

Use search engines and websites to research the following WAN technologies to complete the table below:

Yuki888 [10]

Answer:

Explanation:

I am attaching the table as an image with updated table containing required information for the following WAN technologies.

T1/DS1 => Digital Signal 1 (T-Carrier 1),

T3/DS3 => Digital Signal 3 (T-Carrier 3),

OC3 (SONET) => Optical Carrier 3 (Synchronous Optical Networking),

Frame Relay,

ATM => Asynchronous Transfer Mode,

MPLS => Multi-protocol Label Switching,

EPL => Ethernet Private Line.

Although you have mentioned most of the information yourself, there were some wrong data in it. So I have updated them with correct information in the attached table.

4 0

3 years ago

Read 2 more answers