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Mnenie [13.5K]
3 years ago
5

Software that people commonly use in the workplace to make their lives easier is called

Computers and Technology
1 answer:
Lorico [155]3 years ago
4 0
Software that people commonly use in the workplace to make their lives easier is called system software.
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All of the language commands that the CPU understand make up the CPU's
disa [49]
I think assembly level command mov ,push ,call
5 0
3 years ago
You have the templates of 2 classes, Person and Program. The Person class has 4 attributes, name, age, major and gpa. There is a
Ostrovityanka [42]

Answer:

Hi, I'm going to put the code answer here and you put in the corresponding line to not copy all the code in the answer.

replace the following line or adjust to the following code

/*

* CODE HERE

while(personSelect <= 0 || personSelect  > 5) {

System.out.println("Wrong number, try to input the number in range 1 to 5" );

personSelect = scan.nextInt();

}

if(personSelect == 1){

person1.setGpa(newGPA);

printInfo()

}

else if(personSelect == 2){

person2.setGpa(newGPA);

printInfo()

}

else if(personSelect == 3){

person3.setGpa(newGPA);

printInfo()

}

else if(personSelect == 4){

person4.setGpa(newGPA);

printInfo()

}

else {

person5.setGpa(newGPA);

printInfo()

}

*/

Explanation:

According to the description of code, we have to add some lines to resolve the questions.

a):

In base on the input, we have to modify the <em>attribute GPA</em> with the method <em>setGpa</em> depending on the person chosing. We call the person chosen before and also call the method setGpa( ) and pass  as <em>parameter</em> the GPA value obtained in tha last input

b)

In this case we have to <em>create a loop</em> for iterate the times that is necesary to get a value of person that is permit in <em>range 1 to 5</em>, and hence that we create and individual if condition to assign the GPA to the person chosen.

I hope it's help you.

8 0
3 years ago
How to do this PLEASE HELP 80 points!
sp2606 [1]

When reading the story, you know that the code has been created by humans, so it might actually be english and use concepts like our number system, our computer code system (I'm thinking ASCII), things that you should not assume when decoding a real alien message.

Looking at the numbers I notice that digits 6 to 9 do not occur in the message, which is statistically unexpected. This leads me to believe the number base might be 6 rather than our common base 10. In the story there are insects mentioned. Insects have 6 legs, so this makes sense (after all, our base 10 was based on the number of fingers).

Next, I notice the code 052 appearing regularly, so that could be a space. Let's check a hypothesis. 052 in base 6 is 5*6+2 = 32. 32 is the ASCII code for a space!!

Now, a decoding algorithm is ready to be devised:

"for each number in the sequence, parse it as a base-6 number and then print out its corresponding ASCII value".

The following node.js snippet does this:

var code = ['220','241','255','245','052','313',

           '311','052','312','303','052','312',

           '252','245','052','205','241','251',

           '253','243','052','203','253','302',

           '251','244','303','301','053'];

           

var msg = "";

for (let n of code) {

   msg += String.fromCharCode(parseInt(n,6));

}

console.log(msg);


And the message is.........:

<em>Take us to the Magic Kingdom!</em>

So, do these aliens want to visit Disneyland????

5 0
3 years ago
Consider the following import statement in Python, where statsmodels module is called in order to use the proportions_ztest meth
den301095 [7]

Answer:

a. count of observations that meet a condition (counts), total number of observations (nobs), Hypothesized value of population proportion (value).

Explanation:

In other to use the proportion_ztest method, the need to make import from the statsmodel module ; statsmodels.stats.proportion.proportions_ztest ; this will allow use use the Z test for proportion and once this method is called it will require the following arguments (count, nobs, value=None, alternative='two-sided', prop_var=False)

Where;

nobs = number of observations

count = number of successes in the nobs trial or the number of successes for each independent sample.

Value = hypothesized value of the population proportion.

7 0
3 years ago
I have six nuts and six bolts. Exactly one nut goes with each bolt. The nuts are all different sizes, but it’s hard to compare t
juin [17]

Answer:

Explanation:

In order to arrange the corresponding nuts and bolts in order using quicksort algorithm, we need to first create two arrays , one for nuts and another for bolts namely nutsArr[6] and boltsArr[6]. Now, using one of the bolts as pivot, we can rearrange the nuts in the nuts array such that the nuts on left side of the element chosen (i.e, the ith element indexed as nutArr[i]) are smaller than the nut at ith position and nuts to the right side of nutsArr[i] are larger than the nut at position "I". We implement this strategy recursively to sort the nuts array. The reason that we need to use bolts for sorting nuts is that nuts are not comparable among themselves and bolts are not comparable among themselves(as mentioned in the question)

The pseudocode for the given problem goes as follows:

// method to quick sort the elements in the two arrays

quickSort(nutsArr[start...end], boltsArr[start...end]): if start < end: // choose a nut from nutsArr at random randElement = nutsArr[random(start, end+1)] // partition the boltsArr using the randElement random pivot pivot = partition(boltsArr[start...end], randElement) // partition nutsArr around the bolt at the pivot position partition(nutsArr[start...end], boltsArr[pivot]) // call quickSort by passing first partition quickSort(nutsArr[start...pivot-1], boltsArr[start...pivot-1]) // call quickSort by passing second partition quickSort(nutsArr[pivot+1...end], boltsArr[pivot+1...end])

// method to partition the array passed as parameter, it also takes pivot as parameter

partition(character array, integer start, integer end, character pivot)

{

       integer i = start;

loop from j = start to j < end

       {

check if array[j] < pivot

{

swap (array[i],array[j])

               increase i by 1;

           }

 else check if array[j] = pivot

{

               swap (array[end],array[j])

               decrease i by 1;

           }

       }

swap (array[i] , array[end])

       return partition index i;

}

7 0
3 years ago
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