Question

Joe wants to put a fence around his rectangular garden. His garden measures 33 ft by 39 ft. The garden has a path around it that is 3 ft wide. How much fencing material does Joe need to enclose the garden and path?

Answer 1

Let L = length and w = width 
perimeter = 2L + 2w = 
2(39 + 6) + 2(33 + 6) = 
2(45) + 2(39) = 
90 + 78 = 
168ft 

Answer 2

Answer: 168

Step-by-step explanation:

Given: The dimensions of the garden is 33 ft by 39 ft.

Since the garden has a path around it that is 3 ft wide.

Then, the new dimensions of the garden with path will be (33+2(3)) ft by (39+2(3)) ft or 39 ft by 45 ft.

The perimeter of rectangle is given by :-

$P=2(l+b)\\\\\Rightarrow\ P=2(39+45)\\\\\Rightarrow\ P=2(84)\\\\\Rightarrow\ P=168\ feet$

Hence, the Joe need 168 feet fencing material to enclose the garden and path.