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4 years ago

Find the out what the variable means? -22=12p-2(5p+4) p=____

Mathematics

2 answers:

blondinia [14]4 years ago

8 0

P=9

Hope I helped! :)

Mila [183]4 years ago

4 0

P is equal to 9....... If you need more help let me know

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Does the (1,2) satisfy the equation Y equals 3X

AlekseyPX

No. When you plug in x and y you get 2=3

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3 years ago

View the lane below and calculate the slope by using the slope formula

velikii [3]

Answer:

slope = 4

Step-by-step explanation:

Calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (3, 12) ← 2 points on the line

m = $\frac{12-0}{3-0}$ = $\frac{12}{3}$ = 4

6 0

3 years ago

Read 2 more answers

A square has a perimeter of 40 m what is the length of each side

zubka84 [21]

Answer:

10m

Step-by-step explanation:

Perimeter means adding up all of the sides of a shape.

One property of a square is that all lengths of a square are the same.

We also know squares have 4 sides.

Lets set up an expression to solve the length for each side with variable S representing the length of a side:

4 * S = 40

Divide each side by 4:

S = 10

Therefore, each side of the square has a length 10m

7 0

2 years ago

You have a credit card with a balance of $2,856.74 at a 14.75% APR. You decide to put $629.63/month toward reducing your debt. H

Elenna [48]

629.63*0.1475/12=7.74

6 0

3 years ago

Read 2 more answers

Help please! (no one was answering it in physics and i really need help)

aivan3 [116]

Let $v_0$ be the cat's speed just as it leaves the edge of the table. Then taking the point 1.3 m below the edge of the table to be the origin, the cat's horizontal position at time $t$ is given by

$x(t)=v_0t$

and its height is

$y(t)=1.3\,\mathrm m-gt^2$

where $g$ is 9.8 m/s^2, the magnitude of the acceleration due to gravity.

The time it takes for the cat to hit the ground is $t$ with

$0=1.3\,\mathrm m-gt^2\implies t=\sqrt{\dfrac{1.3\,\rm m}g}\approx0.36\,\mathrm s$

(Unfortunately, this doesn't match any of the given options...)

The cat lands 0.75 m away (horizontally) from the edge of the table, so that its speed $v_0$ was

$0.75\,\mathrm m=v_0(0.36\,\mathrm s)\implies v_0\approx2.08\dfrac{\rm m}{\rm s}$

(Again, not one of the answer choices...)

I'm guessing there's either a typo in the question or answers.

6 0

3 years ago