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4 years ago

What are the zeros of the polynomial function f(x) = x3 - 2x2 - 24x?

Mathematics

2 answers:

emmainna [20.7K]4 years ago

4 0

Answer:

Step-by-step explanation:

first factor out a variable: x(x^2-2x-24)

now solve the quadratic: x(x-6)(x+4)

When you set these expressions equal to zero, you get 0, 6, and -4 as your answers.

Nataliya [291]4 years ago

3 0

First factor out a variable: x(x^2-2x-24)
now solve the quadratic: x(x-6)(x+4)
When you set these expressions equal to zero, you get 0, 6, and -4 as your answers.

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One side of a rectangle is 9 millimeters shorter than six times the other side. Find the length of the longer side if we also kn

vodka [1.7K]

Given:

W(width) = (6L) - 9

L(length) = L

Equation:

2( [ 6L ] - 9) + 2 (L) = 150

= 12L - 18 + 2L = 150

= 12L + 2L = 150 + 18

=14L = 168

L = 168/14, so the length is 12. Let's check our work.

Width: 6(12) - 9 = 72 - 9 = 63

Length: 12

Since there are two lines of width and two lines of length:

2(12) + 2(63) = 24 + 126, which gives you a perimeter of 150 mm.

Hope this helped.

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3 years ago

Help me with math please.

djverab [1.8K]

The answer to that will C and that is easy

3 0

3 years ago

Convert 2 years 3 months into years?

Gnesinka [82]

Answer:

2.25 Years

Step-by-step explanation:

We know that a year has 12 months. So, $\frac{3}{12}=0.25$ . We add this to 2 to get 2.25.

8 0

3 years ago

Read 2 more answers

what types of problems can be solved using the greatest common factor and what types of problems can be solved using the least c

Arisa [49]

The first one is finding the square root of things I believe and I'm not sure about the second one sorry

7 0

3 years ago

ASAP! I really need help with this question! No nonsense answers, and please attach the solution.

uysha [10]

Answer:

$\boxed{\sf Option \ 4}$

Step-by-step explanation:

$\sqrt{2x-3} +x=3$

Subtract x from both sides.

$\sqrt{2x-3} +x-x=-x+3$

$\sqrt{2x-3}=-x+3$

Square both sides.

$( \sqrt{2x-3})^2 =(-x+3)^2$

$2x-3=x^2-6x+9$

Subtract x²-6x+9 from both sides.

$2x-3-(x^2-6x+9 )=x^2-6x+9-(x^2-6x+9)$

$-x^2 +8x-12=0$

Factor left side of the equation.

$(-x+2)(x-6)=0$

Set factors equal to 0.

$-x+2=0\\-x=-2\\x=2$

$x-6=0\\x=6$

Check if the solutions are extraneous or not.

Plug x as 2.

$\sqrt{2(2)-3} +2=3\\ \sqrt{4-3} +2=3\\\sqrt{1} +2=3\\3=3$

x = 2 works in the equation.

Plug x as 6.

$\sqrt{2(6)-3} +6=3\\ \sqrt{12-3} +6=3\\\sqrt{9} +6=3\\3+6=3\\9=3$

x = 6 does not work in the equation.

5 0

4 years ago

Read 2 more answers