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Anna [14]
3 years ago
11

What are the zeros of the polynomial function f(x) = x3 - 2x2 - 24x?

Mathematics
2 answers:
emmainna [20.7K]3 years ago
4 0

Answer:


Step-by-step explanation:

first factor out a variable: x(x^2-2x-24)

now solve the quadratic: x(x-6)(x+4)

When you set these expressions equal to zero, you get 0, 6, and -4 as your answers.


Nataliya [291]3 years ago
3 0
First factor out a variable: x(x^2-2x-24)
now solve the quadratic: x(x-6)(x+4)
When you set these expressions equal to zero, you get 0, 6, and -4 as your answers.
You might be interested in
"find the reduction formula for the integral" sin^n(18x)
dexar [7]
Let

I(n,a)=\displaystyle\int\sin^nax\,\mathrm dx
For demonstration on how to tackle this sort of problem, I'll only work through the case where n is odd. We can write

\displaystyle\int\sin^nax\,\mathrm dx=\int\sin^{n-2}ax\sin^2ax\,\mathrm dx=\int\sin^{n-2}ax(1-\cos^2ax)\,\mathrm dx
\implies I(n,a)=I(n-2,a)-\displaystyle\int\sin^{n-2}ax\cos^2ax\,\mathrm dx

For the remaining integral, we can integrate by parts, taking

u=\sin^{n-3}ax\implies\mathrm du=a(n-3)\sin^{n-4}ax\cos ax\,\mathrm dx\mathrm dv=\sin ax\cos^2ax\,\mathrm dx\implies v=-\dfrac1{3a}\cos^3ax

\implies\displaystyle\int\sin^{n-2}ax\cos^2ax\,\mathrm dx=-\dfrac1{3a}\sin^{n-3}ax\cos^3ax+\dfrac{a(n-3)}{3a}\int\sin^{n-4}ax\cos^4ax\,\mathrm dx

For this next integral, we rewrite the integrand

\sin^{n-4}ax\cos^4ax=\sin^{n-4}ax(1-\sin^2ax)^2=\sin^{n-4}ax-2\sin^{n-2}ax+\sin^nax
\implies\displaystyle\int\sin^{n-4}ax\cos^4ax\,\mathrm dx=I(n-4,a)-2I(n-2,a)+I(n,a)

So putting everything together, we found

I(n,a)=I(n-2,a)-\displaystyle\int\sin^{n-2}ax\cos^2ax\,\mathrm dx
I(n,a)=I(n-2,a)-\left(-\dfrac1{3a}\sin^{n-3}ax\cos^3ax+\dfrac{n-3}3\displaystyle\int\sin^{n-4}ax\cos^4ax\,\mathrm dx\right)
I(n,a)=I(n-2,a)-\dfrac{n-3}3\bigg(I(n-4,a)-2I(n-2,a)+I(n,a)\bigg)+\dfrac1{3a}\sin^{n-3}ax\cos^3ax
\dfrac n3I(n,a)=\dfrac{2n-3}3I(n-2,a)-\dfrac{n-3}3I(n-4,a)+\dfrac1{3a}\sin^{n-3}ax\cos^3ax

\implies I(n,a)=\dfrac{2n-3}nI(n-2,a)-\dfrac{n-3}nI(n-4,a)+\dfrac1{na}\sin^{n-3}ax\cos^3ax
7 0
3 years ago
What is the slope of y=17x+43
goldenfox [79]
The would slope would equal 17
5 0
3 years ago
Read 2 more answers
For every 3 laps that Jackie swims, Ronnie swims 4 laps. During practice, they swam a combined total of 63 laps. How many laps d
Flura [38]

Answer:

36 laps Ronnie swim during practice .

Step-by-step explanation:

Let us assume that the laps that Ronnie swims be x .

Let us assume that the laps that Jackie swims be y .

As given

For every 3 laps that Jackie swims, Ronnie swims 4 laps.

i.e

3 × laps that Ronnie swims = 4 × laps that Jackie swims

3 × x = 4 × y

3x = 4y

Equation becomes

x + y  = 63

Thus by using 3x = 4y .

y = \frac{3x}{4}

Thus

x +\frac{3x}{4} = 63

4x + 3x = 63 × 4

7x = 252

x = 36

Put the value of x in the equation x + y  = 63

36 + y = 63

y = 63 - 36

y = 27

Therefore the 36 laps Ronnie swim during practice .

4 0
3 years ago
PLEASE HELP I WILL REWARD BRAINLIEST !! Correct answers only
Fed [463]
It will shrink trust me 

6 0
2 years ago
14=-3y i need help solving this
Likurg_2 [28]
Y=-14/3 or -4.66666667 repeated
6 0
3 years ago
Read 2 more answers
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