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Valentin [98]
2 years ago
14

A circle has a radius of 26.85 inches what is the circumference of this circle

Mathematics
2 answers:
andrew-mc [135]2 years ago
5 0
The circumference of the circle is 168.7 in
Over [174]2 years ago
3 0
Circumference = 2 x \pi x radius

We'll use 3.14 for Pi

2 x 3.14 = 6.28

6.28 x 26.85 = 168.61800

Round
168.62
or 
168.6
or 
169
(it all depends on how you round)
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Kelly’s baby brother weighs 7.71 is pounds. Her newborn kitten weighs 0.24 pound. How much more does kelly’s baby brother weigh
sleet_krkn [62]

Answer:

7.47

Step-by-step explanation: 7.71-0.24=7.47 which is how you find how much more the baby weighed than the kitten

3 0
3 years ago
Find the area of a triangle and semi circle where the diameter is 18 and the height is 14 using 3.14
Readme [11.4K]

Answer:

triangle A= 1/2bh

1/2(18)(14)= 126

semi circle 3.14(9)^2 divided by 2 = 127.17

Triangle Area plus semi circle Area = 126+127.17= 253.17

4 0
2 years ago
PLEASE HELP ME ANSWER BESTIES !!!
Crazy boy [7]
Your not my bestieeee but the answer from me is unkown i jus want to be able to answer one question :)
5 0
3 years ago
Read 2 more answers
Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 b
jeka94

Answer:

Step-by-step explanation:

From the given information; Let's assume that  R should represent the set of all possible outcomes generated from  a bit string of length 10 .

So; as each place is fitted with either 0 or 1

\mathbf{|R|= 2^{10}}

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0

Now;

if  a 0 bit and a 1 bit are equally likely

The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

\mathbf{P(E) = \dfrac{|E|}{|R|}}

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:

\mathbf{{|E|}=1 }   ; \mathbf{|R|= 2^{10}}

\mathbf{P(E) = \dfrac{1}{2^{10}}}

4 0
3 years ago
VERY URGENT HAVE A TEST TO TAKE
Daniel [21]
The easiest way is to try the point (-4,1), that is, x=-4, y=1,
to see which equation works.
b works.

The usual way to do it is to find the equation of the circle
standard form of a circle is (x-h)²+(y-k)²=r², (h,k) are the coordinates of the center, r is the radius. 
in this case, the center is (-2,1), so (x+2)²+(y-1)²=r²
the given point (-4,1) is for you to find r: (-4+2)²+(1-1)²=r², r=2
so the equation is (x+2)²+(y-1)²=2² 
expand it: x²+4x+4+y²-2y+1=4
x²+y²+4x-2y+1=0, which is answer b.

5 0
3 years ago
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