Simplify 4.2^-3 x 5.1^2 x 4.2^4 x 5.1^3

What are the steps to construct parallel lines using a compass and straightedge?

nevsk [136]

See if the distance between the two lines is consistent with a compass.

Make sure the lines intersect at right angles with the corner of a piece of paper.

Measure each of the angles with a straightedge.

There is no way to ensure you have constructed parallel lines.

4 0

4 years ago

Andrew buys books and videos in a store. He uses the expression 4b + 8v to find the cost of what he is buying, where b is the nu

7nadin3 [17]

Answer:

68

Step-by-step explanation:

1) Plug In (when you plug in you replace the defined variable with the number given. usually you have to find the numbers to plug in but since they're already given to you you just plug them in.) 4(3) + 8(7)=T T= total cost

2) Multiply 4*3=12 8*7=56

3) Add 12+56=68

4) <u>T=68</u>

7 0

3 years ago

What is 3X minus 6 and how did you get there??? A. 7 B. 9 C. 15 D. 18

Brilliant_brown [7]

Multiply 3x by -6, it gives you -18 so I'm going to say D

7 0

3 years ago

Read 2 more answers

Which one?!!! Help plz

nydimaria [60]

I think number 6 it should be right I think

4 0

3 years ago

Please help I will give Brainliest please!

WITCHER [35]

Part (a)

The domain is the set of allowed x inputs of a function.

The graph shows that x = 0 is not allowed because of the vertical asymptote located here. It seems like any other x value is fine though.

<h3>Domain: set of all real numbers but $x \ne 0$ </h3>

To write this in interval notation, we can say $(-\infty, 0) \cup (0, \infty)$ which is the result of poking a hole at 0 on the real number line.

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The range deals with the y values. The graph makes it seem like it stretches on forever in both up and down directions. If this is the case, then the range is the set of all real numbers.

<h3>Range: Set of all real numbers</h3>

In interval notation, we would say $(-\infty, \infty)$ which is almost identical to the interval notation of the domain, except this time of course we aren't poking at hole at 0.

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Part (b)

<h3>The x intercepts are x = -4 and x = 4</h3>

We can compact that to the notation $x = \pm 4$

These are the locations where the blue hyperbolic curve crosses the x axis.

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Part (c)

<h3>Answer: There aren't any horizontal asymptotes in this graph.</h3>

Reason: The presence of an oblique asymptote cancels out any potential for a horizontal asymptote.

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Part (d)

The vertical asymptote is located at x = 0, so the equation of the vertical asymptote is naturally x = 0. Every point on the vertical dashed line has an x coordinate of zero. The y coordinate can be anything you want.

<h3>Answer: x = 0 is the vertical asymptote</h3>

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Part (e)

The oblique or slant asymptote is the diagonal dashed line.

It goes through (0,0) and (2,6)

The equation of the line through those points is y = 3x

If you were to zoom out on the graph (if possible), then you should notice the branches of the hyperbola stretch forever upward but they slowly should approach the "fencing" that is y = 3x. The same goes for the vertical asymptote as well of course.

<h3>Answer: Oblique asymptote is y = 3x</h3>

5 0

3 years ago