Simplifying
j = (2j + 3)
Reorder the terms:
j = (3 + 2j)
Remove parenthesis around (3 + 2j)
j = 3 + 2j
Solving
j = 3 + 2j
Solving for variable 'j'.
Move all terms containing j to the left, all other terms to the right.
Add '-2j' to each side of the equation.
j + -2j = 3 + 2j + -2j
Combine like terms: j + -2j = -1j
-1j = 3 + 2j + -2j
Combine like terms: 2j + -2j = 0
-1j = 3 + 0
-1j = 3
Divide each side by '-1'.
j = -3
Simplifying
j = -3
I’m not hundred percent sure must I believe it’s 0
Answer: The hypotenuse is 53 (approximately)
Step-by-step explanation: In this question we shall apply the Pythagoras theorem which states that;
AC^2 = AB^2 + BC^2
Where AC is the hypotenuse and AB and BC are the two other sides. Having been given that the two other sides are 36 and 39 units respectively, the hypotenuse is now,
AC^2 = 36^2 + 39^2
AC^2 = 1296 + 1521
AC^2 = 2817
Add the square root sign to both sides of the equation
AC = 53.0754
Therefore the hypotenuse is approximately 53 units.
Answer:
i dont know im sorry i wish you the best bro
Step-by-step explanation:
Evaluate is just a fancy term for solve.
So to start you’ll want to substitute in the values that you are given and the just solve the sum.
I really hope this was helpful.
