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Leno4ka [110]
3 years ago
5

Simplify 4.2^-3 x 5.1^2 x 4.2^4 x 5.1^3

Mathematics
1 answer:
Stolb23 [73]3 years ago
5 0

Answer:

14491.060542

Step-by-step explanation:

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Alice bought a 2-foot sub sandwich.The sandwich was cut into 10 pieces. Beth ate 1/5 of the sandwich , Camila ate 3/10 of the sa
9966 [12]

Answer:

Camila

Step-by-step explanation:

you take 1/5 and make it 2/10. Then you see that there are 10 slices and since Beth and Camila ate in 10th's, Beth at 2 slices and Camila ate 3. So since Alice ate 2 slices its less than Camila. Therefore, Camila ate the most slices.

7 0
3 years ago
How to find the slope from a table of data
sammy [17]

The slope of a linear line (or a linear equation) can be found by simply taking 2 values for x and y and then using the slope formula which is \frac{dy}{dx} or:

\frac{y_{2} - y_{1}}{x_{2} - x_{1}}

Example:

Let's say you're give this table:

x: 1, 2

y: 1, 2

Following the steps which I gave, you take 1 value for the y (preferably the larger one) which in this cause will be 2 and then another y from the table which would be 1

Do the same for x

Now plug the values taken in the slope formula and you get:

\frac{2 - 1}{2 - 1}

\frac{1}{1} = 1

Therefore the slope is 1.

6 0
2 years ago
Read 2 more answers
Convert the following decimal to a common fraction. Reduce to lowest terms 0.2 = 2/1 0/2 1/2 1/5
Phoenix [80]
0.2 = \frac{2}{10} = \frac{1}{5}
So, \frac{1}{5}
7 0
3 years ago
Please help me understand
Svetach [21]

Answer/Step-by-step explanation:

The problem replaces the x with the appropriate input. It is asking for you to find the correct output (y). Looking at the graph, when the point hits -1 on the x value, the value for y is 3. So, the correct output is 3.

3 0
2 years ago
Use the surface integral in​ Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus
Tom [10]

Stokes' theorem says the integral of the curl of \vec F over a surface S with boundary C is equal to the integral of \vec F along the boundary. In other words, the flux of the curl of the vector field is equal to the circulation of the field, such that

\displaystyle\iint_S\nabla\times\vec F\cdot\mathrm d\vec S=\int_C\vec F\cdot\mathrm d\vec r

We have

\vec F(x,y,z)=x^2\,\vec\imath+4x\,\vec\jmath+z^2\,\vec k

\implies\nabla\times\vec F(x,y,z)=4\,\vec k

Parameterize the ellipse S by

\vec s(u,v)=\dfrac{u\cos v}{\sqrt5}\,\vec\imath+\dfrac{u\sqrt5\sin v}4\,\vec\jmath

with 0\le u\le1 and 0\le v\le2\pi.

Take the normal vector to S to be

\dfrac{\partial\vec s}{\partial\vec u}\times\dfrac{\partial\vec s}{\partial\vec v}=\dfrac u4\,\vec k

Then the flux of the curl is

\displaystyle\iint_S4\,\vec k\cdot\dfrac u4\,\vec k\,\mathrm dA=\int_0^{2\pi}\int_0^1u\,\mathrm du\,\mathrm dv=\boxed{\pi}

4 0
3 years ago
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