Fist break up each number in the hundreds column add the tens and the ones then add the hundreds to the previous answer
<span>h = –16t 2 + 64t + 8
since both the launch height and target height are identical we can say height is 0
solve for t
0 = -16t^2 + 64t +8
-8(2t^2-8t-1) =0
divide both sides by -8
2t^2-8t -1 = 0
t = 4.12 and -0.121
since it can't be a negative number:
t = 4.12 seconds ( round off as needed)
</span>
Answer:
the answer is 54.7
Step-by-step explanation:
82.6 - 27.9 = 54 7
The equation for KG would be y-14=-1(x-2) and the equation for HG would be y-4=1(x-12).
We first find the slope of KG. The formula for slope is
m=(y₂-y₁)/(x₂-x₁)
Using the points we have for KG, we have
m=(4-14)/(12-2) = -10/10 = -1
The equation for point-slope form is
y-y₁=m(x-x₁)
Using the slope of KG and the first point listed for that line, we have
y-14=-1(x-2)
Now we find the slope of HG:
m=(10-4)/(18-12) = 6/6 = 1
Using the point of intersection for KG and HG, we have
y-4=1(x-12)
The answer to the questions
