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3 years ago

Sarah wants to paint three walls in her family room. Two walls are 18 feet long by 10 feet

Mathematics

1 answer:

Brrunno [24]3 years ago

8 0

Answer:

The total area is 444 ft².

Step-by-step explanation:

First you multiply 18 by 10 for one of the walls you get 180*2 since you have two walls with the same dimension. Next you do 12*7 to get 84. Last you would add 84 to 360 and get 444 ft²

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Roman stands across from a flag pole.

Eva8 [605]

The answer is 13.2 m.
Because we are only given the hypotenuse, adjacent, and theta measurements.
the opposite side is always opposite theta. In this case, theta is 39 degrees. The hypotenuse is always the slant of the triangle, so it is 17 m. And adjacent is obviously the only one left, in this case, it is x.

You have to use sin, cos, or tan for this problem. You would use cos because cos = adjacent /hypotenuse (x/17)

so you would do cos(39) times 17
x = cos(39) * 17
x = .777 * 17
x = 13.21

And it says round to the nearest tenth, so it is 13.2 m.
Hope this helps.

3 0

3 years ago

Read 2 more answers

Any help is appreciated.

Bogdan [553]

Step-by-step explanation:

Hey there!

Now, let's look into figure.

angle ACB = 65° { Base angle of triangle ABC}

angle ACB + angle BAC + angle ABC = 180°

65° + 65° + angle ABC = 180°

angle ABC = 180°-130°

Therefore, angle 50°

angle EBD = 50° ( Vertically opposite angle)

Now;

angle EBD= angle DEB = 50° ( Base angle of triangle BDE )

angle BDE + angle DEB + angle EBD = 180° ( Sum of interior angle)

angle BDE = 180° -100°

Therefore, angle BDE = 80°.

Now, 80° + 14x + 2 = 180° { being linear pair}

14x = 180°-82°

14x = 98°

$x = \frac{98}{14}$

X = 7°

Hope it helps......

3 0

3 years ago

Eddie scored at least 27 point more than half of what Duncan scored.eddie score 58points. Wright an inequality that could be sol

Jobisdone [24]

For this case we have:

Let:

x: number of points scored by Duncan

y: number of points scored by Eddie

We have:

$y\geq27 +\frac{x}{2}$ (1)

$y = 58$ (2)

Substituting (2) in (1):

$58\geq27+\frac{x}{2}$

$58-27\geq\frac{x}{2}$

$31\geq\frac{x}{2}$

$2*31\geqx\\62\geq x$

Thus, Duncan could have scored a maximum of 62 points.

Answer:

$x\leq62$ points scored by Duncan.

5 0

3 years ago

+4 What is the solution of 2x-15 - <0? • -45x51 0 -4 -45 -4

soldier1979 [14.2K]

Answer:

alto 5.340040 to costco

Step-by-step explanation:

7 0

4 years ago

Please help need 100

stiks02 [169]

$\angle EFG\ \text{is supplementary to}\ \angle DBC\ \text{and}\\\\\angle ABC\ \text{is supplementary to}\ \angle DBC\ \text{therefore}\ m\angle EFG=m\angle ABC$

$18x+28+7x+27=180\\\\25x+55=180\ \ \ |-55\\\\25x=125\ \ \ \ |:25\\\\x=5\\\\m\angle EFG=(18x+28)^o=(18\cdot5+28)^o=118^o$

$\text{Answer: A)}\ 118^o$

4 0

4 years ago

Read 2 more answers