The diagram is a bit hard to read but I think the triangle has a base length of 4 and an altitude of 1 (gotten by counting dots). Then the area of the triangle is

= (1/2) bh

= (1/2) 4 * 1 =

Thank you,

MrB

8 0

3 years ago

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point A has coordinates (-5, 3). If point (1, 6) is 3/4 of the way from A to B, what are the coordinates of point B

asambeis [7]

Answer:

The coordinates of point B are (3 , 7)

Step-by-step explanation:

* Lets explain how to solve the problem

- If point (x , y) divides a line segments whose endpoints are $(x_{1},y_{1})$

and $(x_{2},y_{2})$ at ratio $(m_{1}:m_{2})$ from the first point $(x_{1},y_{1})$ , then

$x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}}$ and

$y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}$

∵ Point A = (-5 , 3)

∵ The point of dinision (x , y) = (1 , 6)

∵ Point B = $(x_{2},y_{2})$

- Point (1, 6) is 3/4 of the way from A to B, that means the distances

from A to (1 , 6) is 3 parts and from (1 , 6) to B is (4 - 3) = 1 part

∴ $(m_{1}:m_{2})$ = 3 : 1

∵ $1=\frac{(-5)(1)+x_{2}(3)}{3+1}$

∴ $1=\frac{-5+3x_{2}}{4}$

- Multiply each side by 4

∴ $4=-5+3x_{2}$

- Add 5 to both sides

∴ $9=3x_{2}$

- Divide both sides by 3

∴ $x_{2}=3$

∴ The x-coordinate ob point B is 3

∵ $6=\frac{(3)(1)+y_{2}(3)}{3+1}$

∴ $6=\frac{3+3y_{2}}{4}$

- Multiply each side by 4

∴ $24=3+3y_{2}$

- Subtract 3 to both sides

∴ $21=3y_{2}$

- Divide both sides by 3

∴ $y_{2}=7$

∴ The y-coordinate ob point B is 7

*<em> The coordinates of point B are (3 , 7)</em>

8 0

3 years ago

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Rewrite the given percentage as a fraction. Be sure to reduce the fraction to lowest terms

kaheart [24]

Answer:

0.68 - As Decimal

17/25 - Simplest Form For Fraction

68% - Percent

7 0

3 years ago

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