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NARA [144]
4 years ago
5

What is the greatest perfect square in 650

Mathematics
1 answer:
Ne4ueva [31]4 years ago
3 0

25*25=625. The answer is 25.

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-36 as a fraction in simplest form
Cerrena [4.2K]

Answer:

-1/2

Step-by-step explanation:


7 0
4 years ago
Read 2 more answers
HELP MEEE!! Please evaluating a compound. Inequality using a graph
Irina-Kira [14]

Answer:

\frac{x}{2}

Step-by-step explanation:

From the graph, we can conclude that,

x is less than 2 and not including as there is a hollow circle at the mark 2.

Also, x is greater than or equal to 7 including 7 as there is a solid circle at the mark 7

So, the compound inequality will be x

Now, the option that simplifies to the above inequality is the required answer.

Let us check the first option.

\frac{x}{2}

\frac{x}{2}

Therefore, option 1 simplifies to the above compound inequality.

So, the correct answer is option 1.

6 0
3 years ago
Select the correct answer.
charle [14.2K]

Answer: C

Step-by-step explanation:

4^{-11/3 -(-2/3)=4^{-11/3 + 2/3}=4^{-3}=1/64

5 0
2 years ago
PLEASE HELP For a particular​ transformer, the voltage E in the circuits is related to the number of windings W of wire around t
Masja [62]

Answer:

A voltage of 760V will be produced by 19 windings.

Step-by-step explanation:

Given the equation:

E = 40W

Where E is the Voltage in the circuits

and W is the number of windings

<u>Given</u> that E = 760V

<u>To find:</u> W = ?

<u>Solution:</u> Here, we have the given equation in 2 variables where value of 1 variable is given so other can be easily calculated by putting the value of given variable in the equation.

So, Putting the value of E in the given formula and finding W, the number of windings:

760=40 \times W\\\Rightarrow W = \dfrac{760}{40}\\\Rightarrow W = \dfrac{76}{4}\\\Rightarrow W = 19

So, number of windings for a voltage E = 760V is 19.

A voltage of 760V will be produced by 19 windings.

5 0
3 years ago
Use the remainder theorem to show that (x+1) is a factor of f(x)=2x^3-7x^2-5x+4
Nitella [24]

well, the remainder theorem says that if the polynomial f(x) has a factor of (x-a), then if we just plug in the "a" in f(x) it'll gives a remainder, assuming (x-a) is indeed a factor, then that remainder must be 0, so if f(a) = 0 then indeed (x-a) is a factor of f(x).  After all that mumble jumble, let's proceed, we have (x+1), that means [ x - (-1) ], so if we plug in -1 in f(x), we should get 0, or f(-1) = 0, let's see if that's true.

\begin{array}{llrll} f(-1)&=&2(-1)^3-7(-1)^2-5(-1)+4\\\\ &&2(-1)-7(1)-5(-1)+4\\\\ &&-2-7+5+4\\\\ &&-9+9\\ &&0&~~\checkmark \end{array}

3 0
2 years ago
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