Answer:
The answer is below
Step-by-step explanation:
We need to prove that:
(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.
Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.
Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

Answer: 
<u>Step-by-step explanation:</u>
Note the following identities: tan² x = sec²x - 1

tan² x + sec x = 1
(sec² x -1) + sec x = 1
sec² x + sec x - 2 = 0
(sec x + 2)(sec x - 1) = 0
sec x + 2 = 0 sec x - 1 = 0
sec x = -2 sec x = 1

But what are they midpoints of? AFE, BFC, CEF,AFB?
Answer:
<em> 108 degrees</em>
Step-by-step explanation:
From the diagram we are given
Interior angles are 2x + 1 and 63 degrees
Exterior angle = 5x -2
The sum of interior angles is equal to the exterior angle
2x + 1 + 63 = 5x - 2
2x + 64 = 5x - 2
2x - 5x = -2-64
-3x = -66
x = -66/-3
x = 22
Get the exterior angle:
Exterior angle = 5x-2
Exterior angle = 5(22) - 2
Exterior angle = 110-2
Exterior angle = 108 degrees
<em>Hence the measure of the exterior angle is 108 degrees</em>