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Arturiano [62]
3 years ago
11

Consider the following. (See attachment)

Mathematics
1 answer:
Furkat [3]3 years ago
4 0

Answer:

Area: 16

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Calculus</u>

Derivatives

Derivative Notation

Integrals - Area under the curve

Trig Integration

Integration Rule [Fundamental Theorem of Calculus 1]:                                        \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)

Integration Property [Multiplied Constant]:                                                             \displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Integration Property [Addition/Subtraction]:                                                           \displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx

U-Substitution

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle f(x) = 8sin(x) + sin(8x)

\displaystyle y = 0

Bounds of Integration: 0 ≤ x ≤ π

<u>Step 2: Find Area Pt. 1</u>

  1. Set up integral:                                                                                                 \displaystyle A = \int\limits^{\pi}_0 {[8sin(x) + sin(8x)]} \, dx
  2. Rewrite integral [Integration Property - Addition/Subtraction]:                     \displaystyle A = \int\limits^{\pi}_0 {8sin(x)} \, dx +  \int\limits^{\pi}_0 {sin(8x)} \, dx
  3. [1st Integral] Rewrite [Integration Property - Multiplied Constant]:                \displaystyle A = 8\int\limits^{\pi}_0 {sin(x)} \, dx +  \int\limits^{\pi}_0 {sin(8x)} \, dx
  4. [1st Integral] Integrate [Trig Integration]:                                                         \displaystyle A = 8[-cos(x)] \bigg| \limits^{\pi}_0 +  \int\limits^{\pi}_0 {sin(8x)} \, dx
  5. [1st Integral] Evaluate [Integration Rule - FTC 1]:                                            \displaystyle A = 8(2) +  \int\limits^{\pi}_0 {sin(8x)} \, dx
  6. Multiply:                                                                                                              \displaystyle A = 16 + \int\limits^{\pi}_0 {sin(8x)} \, dx

<u>Step 3: Identify Variables</u>

<em>Identify variables for u-substitution.</em>

u = 8x

du = 8dx

<u>Step 4: Find Area Pt. 2</u>

  1. [Integral] Rewrite [Integration Property - Multiplied Constant]:                     \displaystyle A = 16 + \frac{1}{8}\int\limits^{\pi}_0 {8sin(8x)} \, dx
  2. [Integral] U-Substitution:                                                                                  \displaystyle A = 16 + \frac{1}{8}\int\limits^{8\pi}_0 {sin(u)} \, du
  3. [Integral] Integrate [Trig Integration]:                                                              \displaystyle A = 16 + \frac{1}{8}[-cos(u)] \bigg| \limits^{8\pi}_0
  4. [Integral] Evaluate [Integration Rule - FTC 1]:                                                  \displaystyle A = 16 + \frac{1}{8}(0)
  5. Simplify:                                                                                                             \displaystyle A = 16

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Integration - Area under the curve

Book: College Calculus 10e

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