Answer:
See below ~
Step-by-step explanation:
Sides of a rhombus are equal.
⇒ QT = TS
⇒ x² - 4x - 10 = 6x + 14
⇒ x² - 10x - 24 = 0
⇒ x² + 2x - 12x - 24 = 0
⇒ x (x + 2) - 12 (x + 2) = 0
⇒ (x + 2)(x - 12) = 0
⇒ x = -2 or x = 12
Substitute both values and see which gives a positive value for QT :
<u>When x = -2</u> :
- QT = (-2)² - 4(-2) - 10
- QT = 4 + 8 - 10
- QT = 2
<u>When x = 12</u> :
- QT = (12)² - 4(12) - 10
- QT = 144 - 48 - 10
- QT = 86
The 2 possible answers are :
- x = -2, QT = 2
- x = 12, QT = 86
Answer:
=8p−7.25
Step-by-step explanation:
=(5)(p)+(5)(−1)+(3)(p)+(3)(−0.75)
=5p+−5+3p+−2.25
=5p+−5+3p+−2.25
=(5p+3p)+(−5+−2.25)
=8p+−7.25
1. We assume, that the number 128 is 100% - because it's the output value of the task.
<span>2. We assume, that x is the value we are looking for. </span>
<span>3. If 128 is 100%, so we can write it down as 128=100%. </span>
<span>4. We know, that x is 51% of the output value, so we can write it down as x=51%. </span>
5. Now we have two simple equations:
1) 128=100%
2) x=51%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
128/x=100%/51%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 51% of 128
128/x=100/51
<span>(128/x)*x=(100/51)*x - </span>we multiply both sides of the equation by x
<span>128=1.96078431373*x - </span>we divide both sides of the equation by (1.96078431373) to get x
<span>128/1.96078431373=x </span>
<span>65.28=x </span>
x=65.28
<span>now we have: </span>
<span>51% of 128=65.28</span>
Answer:
unlike terms
Step-by-step explanation:
since the first 9y is squared they cannot be combined since the other isn't squared, they cannot be simplified, nor are they alike
X > 0 and -x < y <span>< 2x There you go, it is infinite applying to those rules.</span>
