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Anarel [89]
3 years ago
11

Determine the recursive function that defines the sequence.

Mathematics
1 answer:
Strike441 [17]3 years ago
5 0
<h2>Answer:</h2>

Option: C is the correct answer.

    C.   f(1)=4\\\\f(n)=5\cdot f(n-1)\ ;\ n\geq 2  

<h2>Step-by-step explanation:</h2>

Recursive Formula--

It is the formula which is used to represent the nth term of a sequence in terms of (n-1)th term of the sequence.

Here we are given a table of values by:

            n            f(n)

            1              4

            2             20

            3             100  

i.e. when n=1 we have:

f(1)=4

Also,

f(2)=20\\\\i.e.\\\\f(2)=5\cdot 4\\\\i.e.\\\\f(2)=5\cdot f(1)

Also,

f(3)=100\\\\i.e.\\\\f(3)=5\cdot 20\\\\i.e.\\\\f(3)=5\cdot f(2)

Hence, the recursive formula is:

f(n)=5\cdot f(n-1)\ for\ n\geq 2

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8.7 *10^2 is the answer
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A particular shade of paint is made by mixing five parts of red paint with seven parts of blue paint. To make the correct shade,
frutty [35]

We get that Shannon did not mix the correct shade as the ratios are not equal.

We are given that a particular shade of paint is made by mixing five parts of red paint with seven parts of blue paint.

This means that the ratio of the paints in that shade is

Red : Blue = 5 : 7.

Now, we are also given that to make the correct shade, Shannon makes 12 quarts of blue paint with 8 quarts of red paint.

Here the ratio becomes:

Red : Blue = 8 : 12

= 4 : 6

= 2 : 3

Now, since both the ratios are not equal, he did not mix the correct shade.

Therefore, we get that Shannon did not mix the correct shade as the ratios are not equal.

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brainly.com/question/2784798

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5 0
2 years ago
cos theta = 4/5, 0˚&lt; theta &lt; 90˚ use the information given to find sin2theta, cos2theta, and tan 2theta
NikAS [45]
First calculate \sin\theta.

\sin^2\theta+\cos^2\theta=1\\\\\sin^2\theta=1-\cos^2\theta\\\\\sin^2\theta=1-\left(\dfrac{4}{5}\right)^2\\\\\\\sin^2\theta=1-\dfrac{16}{25}\\\\\\\sin^2\theta=\dfrac{9}{25}\quad|\sqrt{(\dots)}\\\\\\\sin\theta=\sqrt{\dfrac{9}{25}}\\\\\\\boxed{\sin\theta=\dfrac{3}{5}}

We take positive value of sinθ because 0° < θ < 90°
Now we could calculate sin2θ, cos2θ and tan2θ:

\sin2\theta=2\sin\theta\cos\theta=2\cdot\dfrac{3}{5}\cdot\dfrac{4}{5}=\dfrac{2\cdot3\cdot4}{5\cdot5}=\dfrac{24}{25}\\\\\\\cos2\theta=\cos^2\theta-\sin^2\theta=\left(\dfrac{4}{5}\right)^2-\left(\dfrac{3}{5}\right)^2=\dfrac{16}{25}-\dfrac{9}{25}=\dfrac{7}{25}\\\\\\&#10;\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=\dfrac{\frac{24}{25}}{\frac{7}{25}}=\dfrac{24\cdot25}{7\cdot25}=\dfrac{24}{7}=3\dfrac{3}{7}
5 0
3 years ago
Read 2 more answers
Quiz 2 Problem A big ship drops its anchor. The variable ll l l models the anchor's elevation (in meters) relative to the water'
alexandr1967 [171]

Answer:

Initial height of the anchor is 75 meters.          

Step-by-step explanation:

We are given the following in the question:

l(t)=-2.4t+75

where, I is the anchor's elevation in meter after t seconds dropped from the ship.

We have to find the initial height of anchor that is we have to put t = 0  in the equation.

Putting t = 0, we get,

l(0)=-2.4(0)+75 = 75

Thus, initial height of the anchor is 75 meters.

3 0
3 years ago
Read 2 more answers
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