To find the height that the rocket has reached, we can use the following equation to calculate distance.
s = ut + 1/2 at²
s - distance - h
u - initial velocity - 64 ft/s x 0.3048 m/ft = 19.5 m/s
a - acceleration, since the rocket is travelling upwards against gravitational acceleration, its said to be deceleration. therefore value is -9.8 ms⁻²
t - time taken - t seconds
substituting values in the equation
h = 19.5 ms⁻¹ x t s - 1/2 x 9.8 ms⁻² x (t s)²
h = 19.5t - 4.9t²
Answer:
21sq
Step-by-step explanation:
multiply the l times the w which would be 3x7 and get 21.
(Distribute the minus sign of the subtrahend in each term.)
= 8r⁶s³ – 9r⁵s⁴ + 3r⁴s⁵ – 2r⁴s⁵ + 5r³s⁶ + 4r⁵s⁴
(Add or subtract like terms.)
= 8r⁶s³ – 5r⁵s⁴ + r⁴s⁵ + 5r³s⁶
(If you want to factor out, then...)
= r³s³ (8r³ – 5r²s + rs² + 5s³)
