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AlladinOne [14]
3 years ago
7

Hello can you guys help me with these math problem please!!

Mathematics
2 answers:
brilliants [131]3 years ago
8 0
To get the total number of sandwiches, multiply the amount of sandwiches * the number of sandwiches/tray *number of types of sandwiches

5*6*5=150 sandwiches total

divided by 10 guests=15 sandwiches
yes, Cassandra is correct
sp2606 [1]3 years ago
7 0
The total number of sandwiches Cassandra ordered is 150, however Cassandra is wrong, each guest will only get 3 sandwiches.
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What does the 50th term of this arithmetic sequence: 29,32,35,38
frozen [14]

Answer:

176

Step-by-step explanation:

First term (a) = 29

Common difference (d) = 32 - 29 = 3

For calculating the 50th term , n = 50

Now

t_{50} = a + ( n - 1) d\\t_{50} = 29 + ( 50 - 1 ) *3\\ t_{50} = 29 + 147\\t_{50} = 176

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3 0
3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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Solve for x<br><br> 1/3x=7/6 + 1/9
zimovet [89]

Answer:

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3 0
3 years ago
1) Find the 95 % confidence interval for the mean if σ = 11 , using this sample:
melamori03 [73]

Answer:

The 95 % confidence interval for the mean is between 28.09 and 35.97.

Step-by-step explanation:

Mean of the sample:

30 values.

So we sum all the values and divide by 30.

The sum of all the values(43 + 52 + 18 + ... + 20 + 41) is 961.

961/30 = 32.03

Confidence interval:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{11}{30} = 3.94

The lower end of the interval is the sample mean subtracted by M. So it is 32.03 - 3.94 = 28.09

The upper end of the interval is the sample mean added to M. So it is 32.03 + 3.94 = 35.97

The 95 % confidence interval for the mean is between 28.09 and 35.97.

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3 years ago
PLEASE! HELP ASAP! Which does not explain the effect of the author's use of dialogue?
Zarrin [17]

Answer:

do you need all work shown for this problem

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3 years ago
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