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3 years ago

Hello can you guys help me with these math problem please!!

2 answers:

8 0

To get the total number of sandwiches, multiply the amount of sandwiches * the number of sandwiches/tray *number of types of sandwiches

5*6*5=150 sandwiches total

divided by 10 guests=15 sandwiches
yes, Cassandra is correct

sp2606 [1]3 years ago

7 0

The total number of sandwiches Cassandra ordered is 150, however Cassandra is wrong, each guest will only get 3 sandwiches.

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Please help with this question with steps I'll give brainliest!<br><br> Thanks

harina [27]

Answer:

∠ 1,3,5,7 = 32°

∠2,4,6,8,= 148°

Step-by-step explanation:

From the figure attached,

AB and CD are two parallel lines and another transverse line is intersecting these line at two distinct points.

Since, m∠1 = 32°,

∠1 and ∠4 are supplementary angles [Linear pair of angles]

m∠1 + m∠4 = 180°

32° + m∠4 = 180°

m∠4 = 180° - 32°

m∠4 = 148°

therefore,

m∠1,3,5,7 = 32°

m∠2,4,6,8,= 148°

6 0

3 years ago

Tengo que simplificar esta fracción 84/105:<br><br>¡Ayudarme porfavor!

koban [17]

Answer:

Step-by-step explanation:

84/105 = 4/5

5 0

3 years ago

What are the answers to these questions?

Vladimir79 [104]

12 ) 18
13) 54
14) 28/54 (8weeks x 7 days) = 1/2
18/24 = 3/4
therefore rates not equal
15) 0 and 0 ;1 and 4; 2 and 8;3 and 12

7 0

3 years ago

Nonlinear Systems of Equations

zheka24 [161]

The square root and cube root identities are proved.

According to the statement

we have to find that the use of the square root identity (x − y)2 = x2 − 2xy + y2

And use of cube root identity a3 + b3 = (a + b)(a2 − ab + b2).

So, For this purpose, we know that the

A. Let us assume the two conditions.

So,

2x + 3y = 6 -(1)

4x + 7y = 8 -(2)

Here we use elimination method

So, Multiply 4 with (1) and 2 with (2)

8x + 12y = 24

8x + 14y = 16

Now eliminate x from these equations

-2y = 8

here y is -4.

and the x become

2x + 3y = 6

2x -12 = 6

2x = 18

x = 9.

B. For the use of identity $(x- y)^{2} = x^{2} - 2xy + y^{2}$

Let us assume a number 26 and 28 then fill it in the condition then

$(28- 26)^{2} = 28^{2} - 2(28)(26) + 26^{2}$

Then

$(28- 26)^{2} = 784 - 1456 + 676$

$(28- 26)^{2} = 4$

And we have to prove the cube root identity then

The identity is

$a^{3} + b^{3} = (a + b)(a^{2} - ab + b^{2})$

Then let us assume the number 8 and 9 then

$a^{3} + b^{3} = (a + b)(a^{2} - ab + b^{2})$

$8^{3} + 9^{3} = (8 + 9)(8^{2} - 8*9 + 9^{2})$

$8^{3} + 9^{3} = (17)(64 - 72 + 81)$

$8^{3} + 9^{3} = (17)(73)$

$8^{3} + 9^{3} = (1241)$

Hence by this way we prove the square and cube root identities.

So, The square root and cube root identities are proved.

Learn more about square root and cube root here

brainly.com/question/661780

#SPJ1

3 0

2 years ago

What is 1 6/9 +5 9/7

lisabon 2012 [21]

$\longrightarrow{\green{7 \frac{20}{21}}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

$1 \frac{6}{9} + 5 \frac{9}{7} \\ \\ = \frac{15}{9} + \frac{44}{7} \\ \\ = \frac{15 \times 7}{9 \times 7} + \frac{44 \times 9}{7 \times 9} \\ \\ = \frac{105 + 396}{63} \\ \\ = \frac{501}{63} \\ \\ = \frac{167}{21} \\ \\ = 7 \frac{20}{21}$

$\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}$

6 0

3 years ago