6 friends share 3 fruit bars equally

What is the length of a diagonal of a rectangular picture whose sides are 12" x 17" round to the nearest 10th of an inch

MAXImum [283]

A^2 + b^2 = c^2
12^2 + 17^2 = 485
so c^2=485
so c=22.0 inches

5 0

2 years ago

A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses

Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = average age of the random sample of horses with colic = 12 yrs

$\mu$ = average age of all horses seen at the veterinary clinic = 10 yrs

$\sigma$ = standard deviation of all horses coming to the veterinary clinic = 8 yrs

n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P( $\bar X$ $\geq$ 12)

P( $\bar X$ $\geq$ 12) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\geq$ $\frac{12-10}{\frac{8}{\sqrt{60} } }$ ) = P(Z $\geq$ 1.94) = 1 - P(Z < 1.94)

= 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0

3 years ago

mrs jackson has $90.She spends 1/4 pf her money on food 1/2 of the remainder on clothes and she saves the rest. How many does sh

rodikova [14]

First you want to divide $90 by four. You want to take the answer and divide it by 2.

$90 / 4 = $22.5

22.5 / 2 = Mrs. Jackson saved $11.25.

7 0

3 years ago

Steve has overdrawn his checking account by 27$. His bank account charged him 15$ for an overdraft fee. Then he quickly deposite

Oxana [17]

112. Subtract the fee and add the deposit

4 0

3 years ago

Suppose the probability of an irs audit is 2.8 percent for U.S. taxpayers who file form 1040 and who earn 100,000 or more. What

stiks02 [169]

Answer:

So, the odds that a taxpayer would be audited 28 to 972 or 2.88%

Step-by-step explanation:

Given

Let P(A) = Probability of irs auditing

P(A) = 2.8%

Let n = number of those who earn above 100,000

To get the odds that taxpayer would be audited, we need to first calculated the proportion of those that will be audited and those that won't.

If the probability is 2.8% then 2.8 out of 100 will be audited. That doesn't make a lot of sense since you can't have 2.8 people; we multiply the by 10/10

i.e.

Proportion, P = 2.8/100 * 10/10

P = 28/1000

The proportion of those that would not be audited is calculated as follows;

Q = 1000 - P

By substituton

Q = 1000 - 28

Q = 972

So, the odds that a taxpayer would be audited 28 to 972 or P/Q

P/Q = 28/972

= 0.0288065844

= 2.88% --- Approximately

3 0

3 years ago