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3 years ago

UP TO 50 POINTS ON BRAINLY

Mathematics

1 answer:

Gnoma [55]3 years ago

7 0

Answer:

273.075 millions users

Step-by-step explanation:

We can use the date and users as x and y values for our graph.

point 1 = (1994, 37.5)

point 2 = (1998, 70.0)

point 3 = (2002, 102.5)

We know that linear equation can be represented as y = mx + b

where m is the slope and b is the y intercept value when x equal to 0.

m = (y2 -y1)/(x2-x1) = (102.5 - 37.5)/(2002 -1994)

m = 8.125

Now let's solve for b by using point3 values.

102.5 = 8.125(2002) +b

b = -16163.8

Now predict two years from now. Which is the year 2023.

For year 2023, how many mobile phone usage?

y = 8.125(2023) - 16163.8

y = 273.075 millions users

As for model robustness(reliability), it's fairly good be cause all three data points have consistent 8.125 slope. So the predictivity is fairly accurate.

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Sally’s income has increased by 10% and she decides to change her consumption of macaroni and cheese from 10 boxes to 8 boxes. H

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Answer:

-2; Inferior good

Step-by-step explanation:

Given that,

Initial Quantity = 10 boxes

New Quantity = 8 boxes

Percentage increase in Sally's income = 10%

Change in consumption:

= 8 boxes - 10 boxes

= - 2 boxes

Percentage change in quantity demanded:

= (Change in quantity demanded ÷ Initial quantity) × 100

= (-2 ÷ 10) × 100

= - 20%

Therefore,

Income elasticity of demand:

= percentage change in quantity demanded ÷ Percentage change in income

= - 20% ÷ 10

= -2

Inferior goods are generally have a negative income elasticity of demand which means that an increase in the income of the consumer will lead to reduce the quantity demanded for inferior good and vice versa.

Hence, the good is a inferior type of good.

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vovikov84 [41]

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3 years ago

A researcher would like to estimate p, the proportion of U.S. adults who support recognizing civil unions between gay or lesbian

Minchanka [31]

Answer:

Question 1:

(b) 4,445

Question 2:

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Question 1:

We have no previous estimate for the population proportion, so we use $\pi = 0.5$ .

The sample size is n for which M = 0.015. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.015 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.015\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.015}$

$(\sqrt{n})^2 = (\frac{1.96*0.5}{0.015})^2$

$n = 4268$

Samples above this value should be used, and the smaller sample above this value is of 4445, so the answer is given by option b.

Question 2:

Now we find M for which $n = 2222$ .

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$M = 1.96\sqrt{\frac{0.5*0.5}{2222}}$

$M = 0.021$

So 2.1%, and the correct answer is given by option c.

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