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Greeley [361]
3 years ago
5

Simplify 9 + 7 + n. n + 17 n + 16 16n

Mathematics
2 answers:
tino4ka555 [31]3 years ago
4 0
The answer is n+16. there is addition in the middle
Amanda [17]3 years ago
3 0

Answer:

B) n + 16

Step-by-step explanation:

We are given the expression 9 + 7 + n.

Here we need to simplify.

Simplify means we need to simplify the like terms.

Let's see what a like term is.

If we have the same variable with the same exponent, then they are called like terms.

The constants are the like terms, we can simplify them.

Examples:

2xy, -3xy are the like terms

5xy^2, -8xy^2 are like terms

4, 5, -7, 8 are the like terms.

In the given expression 9 + 7 + n

The like terms are 9 and 7. There are in the operation of addition. So we can add them.

So, 9 + 7 + n

= 16 + n

This can be written as n + 16 by commutative property of addition.

Therefore, the answer is B) n + 16

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What’s the first 6 nonzero multiples of 12?
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A sno-cone machine priced at $139 is on sale for 20% off. The sales tax rate is 6.75%. What is the price of the sno-cone machine
trapecia [35]

Answer:

$127.03

Step-by-step explanation:

A snow cone machine price at $139 is on after for 20 off.

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4 0
3 years ago
Calculate the number of kilograms of mercury required to fill a pool that is 20.0 m x 50.0 m x 10.0 m. The density of mercury is
malfutka [58]

Answer:

m=135000000 Kg

Step-by-step explanation:

To find the number of kilograms of mercury we need to find how to relate density, mass and, volume. For this we shall recall the density formula:

\rho=\frac{m}{V}

where \rho is the density, m is the mass and, V is the volume.

We have the density and want to compute the mass so now we want to know the volume of the pool.

The volume of a rectangular pool is given by the fomula:

V= (length)(heigh)(width).

So for our pool

V= (20)(50)(10).

V= 10000m^{3}.

Our density is in g/mL, so the last thing we need to do before computing the mass is to express the density in Kg/m^{3} (this is because we want our mass in Kg and, we have our volume in m^{3}).

For the density conversion we have to remember that

1000mL = 1L

1L=0.001m^{3}

1000g=1Kg

so

\rho=13.5\frac{g}{mL}*\frac{1000mL}{1L}*\frac{1L}{0.001m^{3}}*\frac{1Kg}{1000g}   =13500\frac{Kg}{m^{3}}.

With this we can finally compute mass:

\rho=\frac{m}{V}

m=\rho*V

m=(13500*10000) Kg

m=135000000 Kg.

4 0
3 years ago
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