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kap26 [50]
3 years ago
15

What is the solution to the inequality -x/10>-11​

Mathematics
2 answers:
Vladimir [108]3 years ago
4 0

Answer:

x<110

Step-by-step explanation:

-x/10>-11

-x>-11*10

-x>-110

x>110

x<110

Inessa [10]3 years ago
4 0

Answer:

x > - 110

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the greater than a sign from both sides of the inequality :

       x / 10 - ( -11 ) > 0

                  x

Simplify   ——

                 10

   x    

 —— -  -11  > 0

  10

Subtracting a whole from a fraction

Rewrite the whole as a fraction using  10  as the denominator :

              -11                -11 • 10

   -11 =  ———  =  ————————

               1                     10  

Equivalent fraction: The fraction thus generated looks different but has the same value as the whole

Common denominator: The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

  x - (-11 • 10)               x + 110

———————  =  ———————

      10                            10

       x + 110

 ———————  > 0

          10

Multiply both sides by  10

Subtract  110  from both sides

           x > -110

Inequality plot for

0.100 x  + 11.000  >  0

x > -110

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motikmotik

Answer:

We conclude that the area of the right triangle is:

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Hence, option A is correct.          

Step-by-step explanation:

From the given right-angled triangle,

  • Base = p+1
  • Perpendicular = 2p-6

Using the formula to determine the area of the right-angled triangle

Area of the right triangle A = 1/2 × Base × Perpendicular

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\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd

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Therefore, we conclude that the area of the right triangle is:

A\:=p^2-2p-3

Hence, option A is correct.                                        

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