Answer:
(x+4)(x-3) or A
Step-by-step explanation:
I'm going to assume that you meant to write x² and not x2
which means we have
x²+x-12
and we need to factor this
to do this we need two numbers that add up to 1 (b) but mulitply to -12 (a*c)
our two numbers are
4, -3
Which means the answer is
(x+4)(x-3)
<span>I would say the answers are A and C.
</span>
Let
n-------> the lesser even number
n+2----> the greater even number
we know that
![3(n+2)=(n-10)](https://tex.z-dn.net/?f=3%28n%2B2%29%3D%28n-10%29)
Solve for n
![3n+6=n-10](https://tex.z-dn.net/?f=3n%2B6%3Dn-10)
Combine like terms
![3n-n=-10-6](https://tex.z-dn.net/?f=3n-n%3D-10-6)
![2n=-16](https://tex.z-dn.net/?f=2n%3D-16)
![n=-8](https://tex.z-dn.net/?f=n%3D-8)
so
![n=-8\\n+2=-8+2=-6](https://tex.z-dn.net/?f=n%3D-8%5C%5Cn%2B2%3D-8%2B2%3D-6)
therefore
<u>the answer is</u>
the lesser even number is ![-8](https://tex.z-dn.net/?f=-8)
the greater even number is ![-6](https://tex.z-dn.net/?f=-6)
Answer:
I THINK it's B, could be wrong.
Step-by-step explanation: