Answer:
There is sufficient evidence that fuel economy goal has been attained.
Step-by-step explanation:
The hypothesis :
H0 : μ < 30.2
H1 : μ ≥ 30.2
The test statistic :
(xbar - μ) ÷ (s/√(n))
xbar = 32.12 ; s = 4.83 ; n = 50
Test statistic :
(32.12 - 30.2) ÷ (4.83/√(50))
1.92 ÷ 0.6830651
T = 2.811
Using the Pvalue from test statistic calculator :
Since we used the sample standard deviation, we use the T distribution
df = n - 1 = 50 - 1 = 49
Pvalue(2.811, 49) ; one tailed = 0.00354
At α = 0.05
Pvalue < α ; then we reject the null and conclude that there is sufficient evidence that fuel economy goal has been attained
Answer:
C 2
Step-by-step explanation:
This is a parabolic function
Notice how we go negative and then positive
y = ax^2 +bx+c
Let x = 0
-5 = a(0) + b(0) +c
c = -5
y = ax^2 + bx -5
Let x = 3
4 = a(3)^2 +b(3) -5
Let x=-3
4 = a(3)^2 -b(3) -5
Add the two equations
4 = a(3)^2 +b(3) -5
4 = a(3)^2 -b(3) -5
----------------------------
8 = 2a (3)^2 - 10
18 = 2 a(9)
18 = 18a
a =1
Solving for b
4 = 1(3)^2 -b(3) -5
4 = 9 -3b -5
4 = 4 -3b
0 = -3b
0 =b
The equation is
y = (x)^2 -5
Letting y = -1
-1 =x^2 -5
Adding 5 to each side
4 = x^2
Taking the square root of each side
±2 = x
x= ±2
Given the choices
Answer:
x=3 e y=4
Step-by-step explanation:
x/2=6/y=27/18
...
x/2=27/18
18.x=2.(27)
18x=54
x=54/18
x= 3
...
6/y=27/18
27y=6.(18)
27y=108
y=108/27
y=4
The equation that expresses the relationship between the number of boxes, b and the number or cans, c would be c = 48b. This is because the number or cans shipped would be the dependent variable to the problem as it is dependent on the number or boxes that ship along with. So if one ships 2 boxes then the number of cans that would be shipped would need to match the final output of cans which is 96, and using the equation, c = 49b it does.
c = 48b
96 = 48(2)
96 = 96.
Technically the first option will also be correct but usually the variable in an algebraic expression comes after the coefficient.
Answer:
Option D. 
Step-by-step explanation:
In this problem
we have
where
B is the Final Investment Value or a Balance
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
in this problem we have
substitute in the formula above
