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PSYCHO15rus [73]

3 years ago

13

HELP PLEASE IMMEDIATELY!! Jordan plans to carpet his living room. The dimensions of his living room are 11 feet by 12 feet. The

carpet is sold for $12.50 per square foot. What is the cost of the carpet for the living room?

1 answer:

irakobra [83]3 years ago

7 0

Answer:

$16.50

Step-by-step explanation:

Multiply 11 by 12

Then times the amount you get from multiplying 11 and 12

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15 ounces of gold cost $6058.50 find the unit rate in dollars per ounce

Vlad [161]

The unit rate in dollars per ounce would be $403.90.
Hope this helps! :D

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3 years ago

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Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,

Sholpan [36]

A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
$d^2=3^2+2^2$
$d^2=9+4$
$d^2=13$
$d= \sqrt{13}$
We can conclude that the distance between my house and the movie theater is $\sqrt{13}$

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
$d^2=6^2+5^2$
$d^2=36+25$
$d^2=61$
$d= \sqrt{61}$
We can conclude that the distance between the police station and the airport is $\sqrt{61}$

C. Distance form the park to the Fire Station:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance from the park to the Fire Station is $\sqrt{10}$

Distance from the stadium to the mall:
$d^2=2^2+1^2$
$d^2=4+1$
$d^2=5$
$d= \sqrt{5}$
We can conclude that the distance from the stadium to the mall is $\sqrt{5}$

D. What is the distance between your house and the mall?
Answer:
$d^2=4^2+4^2$
$d^2=16+16$
$d^2=32$
$d= \sqrt{32}$
$d=4 \sqrt{2}$
We can conclude that the distance between my house and the mall is $4 \sqrt{2}$

What is the distance between the movie theater and the school?
answer:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance between the movie theater and the school is $\sqrt{10}$

7 0

2 years ago

A shopkeeper bought 5 dozen pen for rs 480 . If she sold all the pens at the rate of rs 9 per pen . Find profit / loss percent

lakkis [162]

Answer:

12.5%

Step-by-step explanation:

1 dozen=12

5 dozen= 60

Earnings= 9x60= rs 540

Profit= 540-480= rs 60

Percentage profit= 60/480×100%=12.5%

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2 years ago

Solve the following equation. Please show all work x/x-2+x-1/x+1=-1

Ainat [17]

Im not sure but i think its 1.22474487

sorry just in case its wrong :(

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3 years ago

Evaluate the expression |-16|-|-2|

DIA [1.3K]

<h2>Answer:</h2><h2>14</h2><h2></h2><h2>Hope this helps!!</h2>

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2 years ago

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