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3 years ago

Just type anything for 55 points :)

Mathematics

2 answers:

HACTEHA [7]3 years ago

4 0

Answer:

peanut butter yum

Step-by-step explanation:

anything

leonid [27]3 years ago

3 0

Answer:

hahahaha

Step-by-step explanation:

Anything!

Have a nice day!

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PLEASE HELP WITH THIS MATHS QUESTION thank you :D

trasher [3.6K]

A)106°- angle at the centre is half of the angle at the circumference

b)74°- when a tangent meets a radius a right angle is created(90+90+106)= 286 360-286= 74°

4 0

3 years ago

Which of the point-slope equations below are correct for the line that passes through points (-2, -2) and (2, 1)?

Ne4ueva [31]

Find slope first:
m =y2-y1/x2-x1
m = 1--2/2--2
m = 3/4

Select a point, insert your slope, & put it into point slope form:
y-y1 =m(x-x1)

Your final answers are:

y-1=3/4(x-2)
OR
y+2 =3/4(x+2)

8 0

3 years ago

To find the measure of ∠A in ∆ABC, use the___(Pythagorean Theorem, Law of Sines, Law of Cosines). To find the length of side HI

nadya68 [22]

Part 1) To find the measure of ∠A in ∆ABC, use

we know that

In the triangle ABC

Applying the law of sines

$\frac{a}{sin\ A}=\frac{b}{sin\ B}=\frac{c}{sin\ C}$

in this problem we have

$\frac{a}{sin\ A}=\frac{b}{sin\ theta}\\ \\a*sin\ theta=b*sin\ A\\ \\ sin\ A=\frac{a*sin\ theta}{b} \\ \\ A=arc\ sin (\frac{a*sin\ theta}{b})$

therefore

the answer Part 1) is

Law of Sines

Part 2) To find the length of side HI in ∆HIG, use

we know that

In the triangle HIG

Applying the law of cosines

$g^{2}=h^{2}+i^{2}-2*h*i*cos\ G$

In this problem we have

g=HI

G=angle Beta

substitute

$HI^{2}=h^{2}+i^{2}-2*h*i*cos\ Beta$

$HI=\sqrt{h^{2}+i^{2}-2*h*i*cos\ Beta}$

therefore

the answer Part 2) is

Law of Cosines

3 0

2 years ago

Read 2 more answers

In 2010, the population of a city was 224,000. From 2010 to 2015, the population grew by 6%. From 2015 to 2020, it fell by 4%. H

Sophie [7]

Answer:

people 2010:

224,000

people in 2015:

224,000(1+0.06) =237,440

people in 2020

237440(1-0.04) =227,942

6 0

3 years ago

Solve simultaneously Y=x-2 Y^2=x

omeli [17]

$\left \{ {{y=x-2} \atop {\ y^2=x}} \right. \\ \\ \\
y=x-2 \\
y^2=(x-2)^2=x^2-4x+4 \\ \\ \\
y^2=x \\
x^2-4x+4=x \\
x^2-5x+4=0$

$a=1 \\ b=-5 \\ c=4 \\ \\ x=\frac{-(-5) \pm \sqrt{(-5)^2 - 4 \cdot 1 \cdot 4}}{2 \cdot 1}=\frac{5 \pm \sqrt{25 - 16}}{2}=\frac{5 \pm \sqrt{9}}{2}=\frac{5 \pm 3}{2} \\ \\
x=\frac{5+3}{2} \ \lor \ x=\frac{5-3}{2} \\ \\
x=\frac{8}{2} \ \lor \ x=\frac{2}{2} \\ \\
x=4 \ \lor \ x=1$

$y=4-2 \ \lor \ y=1-2 \\
y=2 \ \lor \ y=-1 \\ \\ \\
 \left \{ {{x=4} \atop {y=2}} \right. \ \lor \ \left \{ {{x=1} \atop {y=-1}} \right.$

8 0

3 years ago

Read 2 more answers

Just type anything for 55 points :)​

Just type anything for 55 points :)