Answer:
Therefore the car takes 2 s to reach a minimum height from the ground before rising again.
Step-by-step explanation:
Given that a roller coaster ride reach a height of 80 feet.
The height above the ground of the roller coaster is modeled by the function
h(t)=10t²-40t+80
where t is measured in second.
h(t)=10t²-40t+80
Differentiating with respect to t
h'(t)= 10(2t)-40
⇒h'(t)=20t-40
To find the minimum height we set h'(t)=0
∴20t-40=0
⇒20t =40
⇒t=2
The height of the roller coaster minimum when t=2 s.
The minimum height of of the roller coaster is
h(2)= 10(2)²-40.2+80
=40-80+80
=40 feet.
Therefore the car takes 2 s to reach a minimum height from the ground before rising again.
Answer:
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Step-by-step explanation:
Answer:
Step-by-step explanation:
h^2=x^2+y^2, since this is a square x=y=s so
220^2=2s^2
2s^2=48400
s^2=24200
s=24200^(1/2)m (exact)
s=155.56m (rounded to nearest hundredth of a meter)
One hectare is equal to 10000m^2
A=24200m^2(h/10000m^2)
A=2.42 hectares
Question isn't complete but we make assumptions in order to complete the question and explain
Answer and explanation:
If we are given a table on calories burned by Robyn on weekdays from Monday to Friday and on this table Robyn burnt 500 calories on Monday and burnt 400 calories on Wednesday, then we are required to determine the ratio of calories burnt on Wednesday to calories burnt on Monday:
Calories burnt on Wednesday = 400
Calories burnt on Monday =500
Ratio of calories burnt on Wednesday to calories burnt on Monday =400/500=4/5
Ratio =4:5
Im not an expert or anything, but i think for the innequality, i would say
as far as the amount of people she can invite, do 500-100=400 because of the setup fee, then, to find how many people she can invite. 400÷6.50 which leaves you with the highest amount of people she can invite without going over budget, as 61.
