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2 years ago

BRAINLIEST ANSWER IS GOING TO BE GIVEN

Mathematics

2 answers:

Nataliya [291]2 years ago

7 0

Yes, you can determine whether a system of linear equations has a solution just by looking at the graph of the equations.

I am not sure what you are needing help with though, since I cannot see the drop down options.

iogann1982 [59]2 years ago

6 0

Answer: here’s the answer.

Step-by-step explanation:

The coordinates of a point satisfies the equation of a line if the point lies on the line

If a single point satisfies the equations of two lines, the point is on both lines, so the lines will intersect at that point.

This means that each point where the two lines touch is a solution to the system of equations

This means that if you substitute the x and y values of the point for x and y in the equations, both equations will be true.

hope this helps!..

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stealth61 [152]

Answer:

Step-by-step explanation:

3x + 28

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3 years ago

16. Giorgio bought a car for $21,000. The value of the car depreciates 5% each year. What will the

Lena [83]

Answer:

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Step-by-step explanation:

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2 years ago

Mr. Morris is going to save money and replace his sailboat's mainsail himself. He must determine the area of the mainsail in ord

e-lub [12.9K]

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2 years ago

Millie has a box of 1 hundred cubes. She also has a bag of 70 cubes. How many trains of 10 cubes can she makes?

melisa1 [442]

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5 0

2 years ago

Read 2 more answers

1. The position of a particle moving along a coordinate axis is given by: s(t) = t^2 - 5t + 1. a) Find the speed of the particle

zimovet [89]

Answer: $\left | 2t-5\right |,\ 2,\ 2t-5$

Step-by-step explanation:

Given

Position of the particle moving along the coordinate axis is given by

$s(t)=t^2-5t+1$

Speed of the particle is given by

$\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=\left | 2t-5\right |$

Acceleration of the particle is

$\Rightarrow a=\dfrac{dv}{dt}\\\\\Rightarrow a=2$

velocity can be negative, but speed cannot

$\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=2t-5$

3 0

2 years ago