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2 years ago

BRAINLIEST ANSWER IS GOING TO BE GIVEN

Mathematics

2 answers:

Nataliya [291]2 years ago

7 0

Yes, you can determine whether a system of linear equations has a solution just by looking at the graph of the equations.

I am not sure what you are needing help with though, since I cannot see the drop down options.

iogann1982 [59]2 years ago

6 0

Answer: here’s the answer.

Step-by-step explanation:

The coordinates of a point satisfies the equation of a line if the point lies on the line

If a single point satisfies the equations of two lines, the point is on both lines, so the lines will intersect at that point.

This means that each point where the two lines touch is a solution to the system of equations

This means that if you substitute the x and y values of the point for x and y in the equations, both equations will be true.

hope this helps!..

You might be interested in

11x + 2y = 68 & 5x + y = 13

matrenka [14]

Answer:

i hope its correct

Step-by-step explanation:

11x + 2y=68 ------------1

5x+y=13 ------------2

y= 13-5x. ------------3

put 3 into 1

11x +2(13-5x) =68

11x +26 -10x =68

x=42

put x =42 into 2

5(42) +y =13

210+y=13

y=13-210

y=197

4 0

2 years ago

87.99 minusss 52.46 HELPPPPPPPPPPPP

torisob [31]

35.53 is the answer I hoped that helped

7 0

3 years ago

2x=8 <br>so find the value of x

melisa1 [442]

Answer:

x = 4

Step-by-step explanation:

2x/2 = 8/2

x =4

6 0

2 years ago

Suppose we are interested in analyzing the weights of NFL players. We know that on average, NFL players weigh 247 pounds with a

tigry1 [53]

Answer:

$SE= \frac{\sigma}{\sqrt{n}} = \frac{47}{\sqrt{30}}= 8.58$

$ME= 1.64 *\frac{\sigma}{\sqrt{n}} = 1.64*\frac{47}{\sqrt{30}}= 14.073$

$\bar X - ME = 237- 14.073 = 222.927$

$\bar X + ME = 237+ 14.073 = 251.073$

$n=(\frac{1.640(47)}{5})^2 =237.65 \approx 238$

So the answer for this case would be n=238 rounded up to the nearest integer

Null hypothesis: $\mu \geq 247$

Alternative hypothesis: $\mu$

$z=\frac{237-247}{\frac{47}{\sqrt{30}}}=-1.165$

$p_v =P(z$

If we compare the p value and the significance level given $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't conclude that the true mean is lower than 247 at 10% of significance.

Step-by-step explanation:

For this case we have the following data given:

$\bar X =237$ represent the sample mean

$\sigma = 47$ represent the population deviation

$n =30$ represent the sample size selected

$\mu_0 = 247$ represent the value that we want to test.

The standard error for this case is given by:

$SE= \frac{\sigma}{\sqrt{n}} = \frac{47}{\sqrt{30}}= 8.58$

For the 90% confidence the value of the significance is given by $\alpha=1-0.9 = 0.1$ and $\alpha/2 = 0.05$ so we can find in the normal standard distribution a quantile that accumulates 0.05 of the area on each tail and we got:

$z_{\alpha/2}= 1.64$

And the margin of error would be:

$ME= 1.64 *\frac{\sigma}{\sqrt{n}} = 1.64*\frac{47}{\sqrt{30}}= 14.073$

The confidence interval for this case would be given by:

$\bar X - ME = 237- 14.073 = 222.927$

$\bar X + ME = 237+ 14.073 = 251.073$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

Replacing into formula (b) we got:

$n=(\frac{1.640(47)}{5})^2 =237.65 \approx 238$

So the answer for this case would be n=238 rounded up to the nearest integer

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is lower than 247 pounds, the system of hypothesis would be:

Null hypothesis: $\mu \geq 247$

Alternative hypothesis: $\mu$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{237-247}{\frac{47}{\sqrt{30}}}=-1.165$

P-value

Since is a left tailed test the p value would be:

$p_v =P(z$

Conclusion

5 0

2 years ago

A restaurant has 75% of its tables being used. Which ratio compares the used tables with all the tables in the restaurant?

prisoha [69]

It’s d I did it myself and got it right

5 0

2 years ago

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