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xxTIMURxx [149]
3 years ago
8

What factors does Jenna need to model for the sides?

Mathematics
2 answers:
mojhsa [17]3 years ago
8 0
Do you know the muffin man 2*+%9272
gizmo_the_mogwai [7]3 years ago
7 0
How does the picture look?
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Which point is an x-intercept of the quadratic equation (x-8)(x+9)
defon

Solve for x in each set of parentheses by setting them to 0:

X -8 = 0

X = 8

X+9 = 0

X =-9

You have two x intercepts (8,0) and (-9,0)

You didn’t list any choices to pick from but it would be either if the ones above.

5 0
3 years ago
Read 2 more answers
Solve for y. <br><br> 3y – 12 = –30 A. –6 B. 32 C. –2 D. 2
kogti [31]
3y-12=-30
3y=-30+12
3y=-18
y=-18/3
y=-6.
Answer: A. 
6 0
3 years ago
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What product is shown by the model?​
Alla [95]

Answer:

85 i think

Step-by-step explanation:

5 0
3 years ago
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Steven purchases a bowl. The diameter of the bowl is 14 cm. What is the circumference of the bowl?
9966 [12]
The C of the bowl is 43.98 because C can be calculated like,  C=pi×d
And pi is about 3.14, and 3.14×14 is about 43.98
7 0
3 years ago
To reduce laboratory​ costs, water samples from five public swimming pools are combined for one test for the presence of bacteri
aleksklad [387]

Answer:

Step-by-step explanation:

Given that:

The numbers of the possible public swimming pools are 5

From past results, we have 0.007 probability of finding bacteria in a public swimming area.

In the public swimming pool, the probability of not finding bacteria = 1 - 0.007

= 0.993

Thus;

Probability of combined   =  Probability that at least one public

sample with bacteria           swimming area have bacteria

Probability of combined sample with bacteria  = 1 - P(none out of 5 has          

                                                                                bacteria)

   

Probability of combined sample with bacteria = 1 - (0.993)⁵        

= 1 - 0.9655

= 0.0345

Thus, the probability that the combined sample from five public swimming areas will show the presence of bacteria is 0.0345

From above, the probability that the combined sample shows the presence of bacteria is 0.0345 which is lesser than 0.05.

Thus, we can conclude that;  Yes, the probability is low enough that there is a need for further testing.

6 0
3 years ago
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