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3 years ago

(3x + 10) (2x + 15) what is the value of x ?

Mathematics

1 answer:

Mars2501 [29]3 years ago

5 0

Answer:
6x^2 + 65x + 150

Explanation:

(3x+10)(2x+15)
6x^2 + 45x + 20x + 150
6x^2 + 65x + 150

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Rewrite the inequality into slope Intercept form. 6x-2y>-2 PLEASE PLEASE PLEASE HELP!!!

BARSIC [14]

Answer:

I think it's y < 3x +1

Step-by-step explanation:

subtract 6x to the right side. that's -2y > -6x - 2. then divide -2 out of y, now you have to flip the sign. Now you have y < 3x + 1

5 0

2 years ago

Read 2 more answers

Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

$\displaystyle= \sin(2\theta)$

Using an double-angle identity:

$=2\sin(\theta)\cos(\theta)$

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

4 0

3 years ago

Food and clothing are shipped to victims of a natural disaster. Each carton of food will feed 13 people, while each carton of c

lutik1710 [3]

Answer:

233 cartons of food; 467 cartons of clothing

Step-by-step explanation:

This linear programming problem can be formulated as two inequalities (in addition to the usual constraints that the variables be non-negative). One of these expresses the constraint on weight. Let f and c represent numbers of food and clothing containers, respectively.

40f +25c ≤ 21000

The other expresses the limit on volume.

20f + 5c ≤ 7000

_____

Feasible Region vertex

We can subtract the boundary line equation of the first inequality from that of 5 times the second to find f:

5(20f +5c) -(40f +25c) = 5(7000) -21000

60f = 14000

f = 233 1/3

The second boundary line equation can be rearranged to find c:

c = 1400 -4f = 466 2/3

The nearest integer numbers to these values are ...

(f, c) = (233, 467)

The other vertices of the feasible region are associated with one or the other variable being zero: (f, c) = (0, 840) or (350, 0).

Check of Integer Solution

Trying these in the constraint inequalities gives ...

40·233 +25·467 = 20,995 < 21000
20·233 +5·467 = 6995 < 7000

Selection of the Answer

The answer to the question will be the feasible region vertex that maximizes the number of people helped. That is, we want to maximize ...

p = 13f + 6c

The values of p at the vertices are ...

p = 13·233 + 6·467 = 5831

p = 13·0 + 6·840 = 5040

p = 13·350 + 6·0 = 2100

The most people are helped when the plane is filled with 233 food cartons and 467 clothing cartons.

7 0

3 years ago

Find the distance between the points (0, 2) and (4, 5).

miv72 [106K]

Answer:

3/4

Step-by-step explanation:

8 0

3 years ago

Riley has set up a six week payment schedule to pay for his upcoming school camp. he has already put down a 15 percent deposit a

anyanavicka [17]

Answer:

$32.30 each week

Step-by-step explanation:

Deposit = 15% = $34.20

⇒ total cost of camp = (34.20 ÷ 15) x 100 = $228

Balance left after deposit = 228 - 34.20 = $193.80

If paying the remaining balance in 6 weekly installments,

⇒ weekly payment = 193.80 ÷ 6 = $32.30

4 0

2 years ago