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3 years ago

In the following figure, JL is tangent to circle o at point K.

Mathematics

1 answer:

mixer [17]3 years ago

6 0

Answer:

Step-by-step explanation:

the angle formed by radius and tangent are right angles

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An element with mass 210 grams decays by 8.3% per minute. How much of the element is remaining after 15 minutes, to the nearest

GarryVolchara [31]

Answer:

$57.2\ g$

Step-by-step explanation:

In this problem we have a exponential function of the form

$f(x)=a(b^x)$

where

f(x) is the remaining mass of the element in grams

x is the time in minutes

a is the initial value (y-intercept of the exponential function)

b is the base

r is the rate

$b=(1+r)$

In this problem we have

$a=210\ g$

$r=-8.3\%=-8.3/100=-0.083$ ---> is negative because is a decay's rate

$b=(1-0.083)=0.917$

substitute

The exponential function is equal to

$f(x)=210(0.917^x)$

For x=15 minutes

substitute in the function

$f(x)=210(0.917^15)$

$f(x)=57.2\ g$

4 0

3 years ago

Extra points I'm just confused and cant find the answer

slavikrds [6]

Its B
the answer is above..................................ok

6 0

3 years ago

Read 2 more answers

An electrician charges $40 per visit, and $20 per hour of work. On a particular day, he made 3 visits and calculated that his av

saw5 [17]

Answer:

4 hours

Step-by-step explanation:

For three visits, the electrician earned $40 × 3 = $120 in "per-visit" charges. For working x hours, he earned 20x in "per-hour" charges. The total of these came to 50x:

120 +20x = 50x

120 = 30x . . . . . . . . subtract 20x

4 = x . . . . . . . . . . . . . divide by 30

The electrician worked 4 hours that day.

3 0

3 years ago

Jamie has a deck of 60 sports cards, of which some are baseball cards and some are football cards. Jamie pulls out a card random

natita [175]

Answer:

I'd say 20

Step-by-step explanation:

4 0

4 years ago

The amount of money a worker makes varies directly with the hourly rate of pay. Worker A earns $168 for an 8 hour period. Worker

Nataly_w [17]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------$

$\bf \textit{money varies directly with hourly rate of pay}\qquad \stackrel{money}{m}=k\stackrel{hour~pay}{h}
\\\\\\
\textit{we also know that }
\begin{cases}
m=168\\
h=8
\end{cases}\implies 168=k8\implies \cfrac{168}{8}=k
\\\\\\
21=k\qquad therefore\qquad \boxed{m=21h}
\\\\\\
\textit{now, when h = 6, what is \underline{m}?}\qquad m=21(6)$

3 0

3 years ago