Question

Assume there is a variable , h already associated with a positive integer value. Write the code necessary to count the number of perfect squares whose value is less than h , starting with 1 . (A perfect square is an integer like 9 , 16 , 25 , 36 that is equal to the square of another integer (in this case 3*3 , 4*4 , 5*5 , 6*6 respectively).) Assign the sum you compute to a variable q For example, if h is 19 , you would assign 4 to q because there are perfect squares (starting with 1 ) that are less than h are: 1 , 4 , 9 , 16 .
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Answer 1

Answer:

pseudo code:

x=1

q=0

while x*x<h: {

x += 1}

q=x-1

complete code in C language

#include <stdio.h>

int main() {    

   int h=19;

  int q=0;

   int x=1;

  while ((x*x)<h){

 x += 1;

   }

   q=(x-1);

   printf("The sum of total perfect squares less than %d is: %d", h,q);

   

   return 0;

}

Explanation:

first '%d' in print statement refers to h and second '%d' in print statement refers to q