3 years ago

Hello, please help me with this question, thank you very much.

Mathematics

1 answer:

LUCKY_DIMON [66]3 years ago

7 0

Answer:

(A) <BAC = <ABC

(B) <C = 68°

( 2 * <A + <C = 180°)

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Tanzania [10]

Volume of cylinders = pi x r^2 x height

Simplifying the ratio:
1.6/3 = 16 / 30 (multiply and divide by 10 to remove the decimal)
<span>
Volume Ratio = 512:27</span>

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3 years ago

Read 2 more answers

Kim is watching a space shuttle launch from an observation spot 2 miles away. Find the angle of elevation from Kim to the space

hammer [34]

Answer:

Step-by-step explanation:

Find the diagrammatic representation in the attachment given.

We can see that the diagram is a right angled triangle. To get the angle of elevation, we will use one of the trigonometry identity SOH, CAH, TOA.

Given the adjacent of the triangle to be 2miles (observation spot from the point of launch)and the opposite (side facing the elevation angle) as 2.1miles (the height), we will use TOA.

tan∅ = opposite/adjacent

tan∅ = 2.1/2

tan∅ = 1.05

∅ = tan⁻¹1.05

∅ = 46.4°

<em>Hence the angle of elevation from Kim to the space shuttle, which is at a height of 2.1 miles is approximately 46.4°</em>

5 0

3 years ago

A complex number z_1z 1 z, start subscript, 1, end subscript has a magnitude |z_1|=6∣z 1 ∣=6vertical bar, z, start subscript

aliina [53]

Answer:

The answer is " $\bold{9.19- 9.19\ i}$ "

Step-by-step explanation:

When the value of $z_1$ has the following properties:

$\to |z_1| =13$

$\theta = 315^{\circ} \\\\ = 1.75 \pi\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ _{where} \ \ (\pi = 180^{\circ})$

Calculating the value of $z_1$ :

$= 13 \times [ \cos(1.75 \pi ) + i \sin(1.75 \pi) ] \\\\= 13 \times[\cos(1.75 \pi - 2\pi ) + \ i \sin(1.75 \pi - 2\pi )]\\ \\= 13 \times [\cos(-0.25 \pi ) +\ i \sin(-0.25 \pi) ]\\\\= 13 \times [0.707106781 - 0.707106781]\\\\ =9.19 - 9.19\ i \\\\$