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3 years ago

12

The measure of the exterior angle of the triangle is

1 answer:

Nookie1986 [14]3 years ago

4 0

Answer:

jsjsjsisusbbdbdjsjcjdjsjjsjsjsjsjdjxjx

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How do you solve for the quotient of (x^-1) - 1 ÷ x - 1?

Ber [7]

$\bf x^{-1}-1\div x-1\implies \implies \cfrac{1}{x}-1\div x-1\implies \cfrac{\frac{1}{x}-1}{~~x-1~~}\implies \cfrac{~~\frac{1-x}{x}~~}{\frac{x-1}{1}} \\\\\\ \cfrac{1-x}{x}\cdot \cfrac{1}{x-1}\implies \cfrac{-(\begin{matrix} x-1 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix})}{x}\cdot \cfrac{1}{\begin{matrix} x-1 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}\implies -\cfrac{1}{x}\implies -x^{-1}$

3 0

3 years ago

Can y’all help me with number 2

Lilit [14]

False
true
false
false
Mark brainliest please

5 0

3 years ago

Read 2 more answers

Which sets of values can be the measures of the exterior angles of a triangle?

romanna [79]

The 3 angles must add up to 360 degrees

Only 1 and 4 fit the bill.

5 0

3 years ago

THANKS FOR ANSWERING <br> ✔✔

Fantom [35]

Answer:

-14 1/2, -14, 10/20, 0.6

7 0

3 years ago

Solve for x. Round your answer to the nearest hundredth.

Zarrin [17]

Answer:

Option B is correct

Step-by-step explanation:

2x² - 6x + 3 = 0

Using Quadratic formula:

x = $\frac{-b+-\sqrt{b^{2}-4ac}}{2a}$

a = 2, b = -6, c = 3

x = $\frac-(-6)+-{\sqrt{(-6)^{2}-4(2)(3)}}{2(2)}$

x = $\frac{-(-6)+-\sqrt{(-6)^{2}-4(2)(3)}}{2(2)}\\$

$=\frac{6+-\sqrt{36-24}}{4}\\\\=\frac{6+-\sqrt{12}}{4}\\\\=\frac{6+-3.46}{4}\\\\$

$=\frac{6+3.46}{4}$

x = 2.37

$=\frac{6-3.46}{4}$

x = 0.63

5 0

3 years ago

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