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3 years ago

8

An 11 letter word for the variable in an algebraic expression

2 answers:

Natalija [7]3 years ago

8 0

I'm just guessing but maybe expressions

Anna11 [10]3 years ago

5 0

<span>coefficient: are the number parts with terms for the variables.</span>

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Which of the following statements is no True?

bezimeni [28]

Answer:

correct answer is A. because the square root of 122 is 11.06 which means its between 11 and 12, not 10 and 11

Step-by-step explanation:

4 0

2 years ago

Y-4=-5 (x+3) in point slope form

aniked [119]

The answer is C, slope = -5; point = (-3, 4).

The point slope form of a line is y - y₁ = m (x - x₁), with (x₁, y₁) being the coordinates of one of the points of a line. Here, the first step is to find out what the slope is. The slope is the value in front of (x + 3), which is -5. Now we need to find the coordinates of the point. Since -y₁ is equal to -4, the coordinate of the y value is 4. Now onto the x value. Since -x₁ = 3, the coordinate of the x value is -3. That means that the answer is C, slope = -5; point = (-3, 4).

7 0

3 years ago

A man starts walking north at 2 ft/s from a point P. Five minutes later a woman starts walking south at 3 ft/s from a point 500

Vedmedyk [2.9K]

Answer:

The rate at which both of them are moving apart is 4.9761 ft/sec.

Step-by-step explanation:

Given:

Rate at which the woman is walking, $\frac{d(w)}{dt}$ = 3 ft/sec

Rate at which the man is walking, $\frac{d(m)}{dt}$ = 2 ft/sec

Collective rate of both, $\frac{d(m+w)}{dt}$ = 5 ft/sec

Woman starts walking after 5 mins so we have to consider total time traveled by man as (5+15) min = 20 min

Now,

Distance traveled by man and woman are $m$ and $w$ ft respectively.

⇒ $m=2\ ft/sec=2\times \frac{60}{min} \times 20\ min =2400\ ft$

⇒ $w=3\ ft/sec = 3\times \frac{60}{min} \times 15\ min =2700\ ft$

As we see in the diagram (attachment) that it forms a right angled triangle and we have to calculate $\frac{dh}{dt}$ .

Lets calculate h.

Applying Pythagoras formula.

⇒ $h^2=(m+w)^2+500^2$

⇒ $h=\sqrt{(2400+2700)^2+500^2} = 5124.45$

Now differentiating the Pythagoras formula we can calculate the rate at which both of them are moving apart.

Differentiating with respect to time.

⇒ $h^2=(m+w)^2+500^2$

⇒ $2h\frac{d(h)}{dt}=2(m+w)\frac{d(m+w)}{dt} + \frac{d(500)}{dt}$

⇒ $\frac{d(h)}{dt} =\frac{2(m+w)\frac{d(m+w)}{dt} }{2h}$ ...as $\frac{d(500)}{dt}= 0$

⇒ Plugging the values.

⇒ $\frac{d(h)}{dt} =\frac{2(2400+2700)(5)}{2\times 5124.45}$ ...as $\frac{d(m+w)}{dt} = 5$ ft/sec

⇒ $\frac{d(h)}{dt} =4.9761$ ft/sec

So the rate from which man and woman moving apart is 4.9761 ft/sec.

3 0

3 years ago

AD is altitude of ΔABC and DE is altitude of ΔBEC. If m∠ADB=4x+15, what is m∠EDC?

Anna35 [415]

Answer:

m∠EDC = 4x+15 (vertically opposite angles are equal)

Step-by-step explanation:

Please find the attached document for explanation

7 0

2 years ago

Hey I'm Chloe Can you Help Me, I will give Brainlest, Thank you :)

almond37 [142]

Answer:

The sample is the amount of people because not everyone is getting chosen

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers